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                              Q:
                           
                           
                                                      | A) 1/36 | B) 91/256 | 
| C) 13/256 | D) 43/256 | 
                              Answer:   B) 91/256
                              
                                                            
                              
Explanation:
                               
                           
                           Explanation:
Find the number of cases in which none of the digits show a '6'. 
i.e. all three dice show a number other than '6', 5×5×5=125 cases. 
Total possible outcomes when three dice are thrown = 216.
The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.
=216−125=91
The required probability = 91/256
 
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