A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?
A) 48 sec
B) 36 sec
C) 18 sec
D) 72 sec
Answer: B) 36 sec
Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr =(36*5/18) m/sec = 10 m/sec
The distance between two stations, A and B, is 428 km.A train starts from station ‘A’ at 6:00 a.m. and moves towards station ‘B’ at an average speed of 48 km/h. Another train starts from station ‘B’ at 6:20 a.m. and moves towards station ‘A’ at an average speed of 55 km/h. At what time will the trains meet?
Two stations L and M are 180 km apart from each other. A train leaves from L to M and simultaneously another train leaves from M to L. Both trains meet after 9 hours. If the speed of the first train is 10 km/hr more than the second train, then what is the speed (in km/hr) of the slower train?
X and Y are two stations which are 280 km apart. A train starts at a certain time from X and travels towards Y at 60 km/h. After 2 hours, another train starts from Y and travels towards X at 20 km/h. After how many hours does the train leaving from X meets the train which left from Y?