A) Rs.1200 | B) Rs.1230 |

C) Rs.1260 | D) Rs.1290 |

Explanation:

Let the new S.P be x, then

(100 - loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)

$\Rightarrow \left(\frac{95}{1140}=\frac{105}{x}\right)$

=> x = 1260

A) 35% | B) 28% |

C) 22% | D) 19% |

Explanation:

Given the cost price of the articles = Rs. 450

To get overall 20% gain,

Total Selling Price = (20/100) x 450 = 540

One third of the CP = 1/3 x 450 = Rs. 150

But given 1/3 of articles are sold at 10% loss

S.P of 1/3 of articles = 90% of 150

= 90 x 150/100 = 135

Then, S.P on remaining 2/3 goods must be

= 450 - 135 = 405 ...........(1)

CP on remaining goods

= 2/3 x 450 = 300 ............(2)

Profit = SP - CP = 405 - 300 = 105

Profit % = (105/300) x 100

= 35%.

A) loss of 24% | B) gain of 28% |

C) loss of 28% | D) gain of 20% |

Explanation:

Money invested by Rajan before 1 year was = Rs. 100000

Money in UK pounds @ 75 is = **100000/75 = 1333.33 Pounds**

Now, after 1 year invested amount was appreciated by 20%

=> **20% of 1333.33 = 266.66**

Total investment becomes = 1333.33 + 266.66 = 1600 Pounds

This 1600 Pounds @ Indian currency at 80 = **1600 x 80 = Rs. 1,28,000**

Hence, Rajan's investment of Rs. 1,00,000 becomes Rs. 1,28,000 in 1 year

Therefore, his profit % = **[(128000 - 100000)/100000] x 100 = 28%.**

A) 33.33% | B) 22.22% |

C) 11.11% | D) 1% |

Explanation:

Let the cost price of 1 article = Rs. 1

From the given data,

Then, the selling price of 1 article = 22/18 = 11/9

Then, Profit = SP - CP = 11/9 - 1 = 2/9

Required, profit % = Profit/CP x 100

= [(2/9)/1] x 100

= 200/9

= 22.222%.

A) Rs. 1190 | B) Rs. 1288 |

C) Rs. 1365 | D) Rs. 1452 |

Explanation:

Let the profit be Rs. p

Then Cost price of the bag = 340p/100 = 3.4p

According to question,

3.4p + p = 1540

4.4p = 1540

p = 1540/4.4

p = 350

The profit p = Rs, 350

Hence, The cost price of the bag = **3.4p = 3.4 x 350 = Rs. 1190.**

A) Rs. 1000 | B) Rs. 1020 |

C) Rs. 1040 | D) Rs. 980 |

Explanation:

Let the marked price of the router be Rs. P

From the given data,

$\mathbf{P}\mathbf{}\mathbf{x}\mathbf{}\frac{\mathbf{85}}{\mathbf{100}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{P}\mathbf{}\mathbf{x}\mathbf{}\frac{\mathbf{80}}{\mathbf{100}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{51}\phantom{\rule{0ex}{0ex}}\mathrm{P}\mathrm{x}\frac{5}{100}=51\phantom{\rule{0ex}{0ex}}\mathbf{\Rightarrow}\mathbf{}\mathbf{P}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{5100}}{\mathbf{5}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{1020}\mathbf{}$

Hence, the original marked price of the router is Rs. 1020.

A) Rs. 250 | B) Rs. 125 |

C) Rs. 225 | D) Rs. 200 |

Explanation:

Initial amount spent on trouser by the man = Rs. 1250

Now, by the reduction of 20% in 1250, he can buy t-shirt too.

=> t-shirt cost = 20% of 1250 = 20 x 1250/100 = 250

Therefore, the price of the t-shirt = **Rs. 250.**

A) 20% | B) 40% |

C) 45% | D) 35% |

Explanation:

Cost price = Rs. 30

Selling price = Rs. 50

Gain = Rs. 20

Profit % = Gain/cost price x 100 = 20/50 x 100 = 40%

A) RS. 200 | B) Rs. 160 |

C) Rs. 100 | D) Rs. 40 |

Explanation:

The first lost Rs. 100, but after the thief bought Rs. 60 goods, he get that Rs. 100 back but he lost Rs. 60 value of goods and Rs. 40 in change.

So, a total of 60 + 40 = 100 Rs. the owner lose.