A) Rs. 70 | B) Rs. 72 |

C) Rs. 74 | D) Rs. 76 |

Explanation:

We Know, $S.P=\left(\frac{100+gainpercent}{100}\times C.P\right)$

$\Rightarrow C.P=\frac{100}{122.50}\times 392$

Profit = 392−320 = Rs72

A) Rs. 47 | B) Rs. 49.2 |

C) Rs. 48.5 | D) Rs. 50.3 |

Explanation:

Total cost of all varieties of mangoes = 20 x 2 + 40 x 3 + 50 x 5 = 40 + 120 + 250 = Rs. 410

Then, cost of 1 kg mangoes = 410/10 = Rs. 41

To get 20% profit,

The rate at which the mangoes should be sell = 120/100 x 41 = **Rs. 49.2**

A) Rs. 10.75 | B) Rs. 11.25 |

C) Rs. 12 | D) Rs. 13.50 |

Explanation:

Total quantity of sugar **= 45 + 30 = 75**

Gain or loss can be calculated as

9.75 x 75 - (30 x 9 + 45 x 10)

= 731.25 - 720

**= 11.25**

Hence, in the overall transaction, Rishi got **Rs. 11.25 gain.**

A) 35% | B) 28% |

C) 22% | D) 19% |

Explanation:

Given the cost price of the articles = Rs. 450

To get overall 20% gain,

Total Selling Price = (20/100) x 450 = 540

One third of the CP = 1/3 x 450 = Rs. 150

But given 1/3 of articles are sold at 10% loss

S.P of 1/3 of articles = 90% of 150

= 90 x 150/100 = 135

Then, S.P on remaining 2/3 goods must be

= 450 - 135 = 405 ...........(1)

CP on remaining goods

= 2/3 x 450 = 300 ............(2)

Profit = SP - CP = 405 - 300 = 105

Profit % = (105/300) x 100

= 35%.

A) loss of 24% | B) gain of 28% |

C) loss of 28% | D) gain of 20% |

Explanation:

Money invested by Rajan before 1 year was = Rs. 100000

Money in UK pounds @ 75 is = **100000/75 = 1333.33 Pounds**

Now, after 1 year invested amount was appreciated by 20%

=> **20% of 1333.33 = 266.66**

Total investment becomes = 1333.33 + 266.66 = 1600 Pounds

This 1600 Pounds @ Indian currency at 80 = **1600 x 80 = Rs. 1,28,000**

Hence, Rajan's investment of Rs. 1,00,000 becomes Rs. 1,28,000 in 1 year

Therefore, his profit % = **[(128000 - 100000)/100000] x 100 = 28%.**

A) 33.33% | B) 22.22% |

C) 11.11% | D) 1% |

Explanation:

Let the cost price of 1 article = Rs. 1

From the given data,

Then, the selling price of 1 article = 22/18 = 11/9

Then, Profit = SP - CP = 11/9 - 1 = 2/9

Required, profit % = Profit/CP x 100

= [(2/9)/1] x 100

= 200/9

= 22.222%.

A) Rs. 1190 | B) Rs. 1288 |

C) Rs. 1365 | D) Rs. 1452 |

Explanation:

Let the profit be Rs. p

Then Cost price of the bag = 340p/100 = 3.4p

According to question,

3.4p + p = 1540

4.4p = 1540

p = 1540/4.4

p = 350

The profit p = Rs, 350

Hence, The cost price of the bag = **3.4p = 3.4 x 350 = Rs. 1190.**

A) Rs. 1000 | B) Rs. 1020 |

C) Rs. 1040 | D) Rs. 980 |

Explanation:

Let the marked price of the router be Rs. P

From the given data,

$\mathbf{P}\mathbf{}\mathbf{x}\mathbf{}\frac{\mathbf{85}}{\mathbf{100}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{P}\mathbf{}\mathbf{x}\mathbf{}\frac{\mathbf{80}}{\mathbf{100}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{51}\phantom{\rule{0ex}{0ex}}\mathrm{P}\mathrm{x}\frac{5}{100}=51\phantom{\rule{0ex}{0ex}}\mathbf{\Rightarrow}\mathbf{}\mathbf{P}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{5100}}{\mathbf{5}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{1020}\mathbf{}$

Hence, the original marked price of the router is Rs. 1020.

A) Rs. 250 | B) Rs. 125 |

C) Rs. 225 | D) Rs. 200 |

Explanation:

Initial amount spent on trouser by the man = Rs. 1250

Now, by the reduction of 20% in 1250, he can buy t-shirt too.

=> t-shirt cost = 20% of 1250 = 20 x 1250/100 = 250

Therefore, the price of the t-shirt = **Rs. 250.**