2
Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

 

An artificial kund is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the kund at the same time during which the kund is filled by the third pipe alone. The second pipe fills the kund 5 hours faster than the first pipe and 4 hours slower than the third pipe.

Quantity 1: The time required by the first pipe?

Quantity 2: Time taken by all three pipes to fill the Kund simultaneously

A) Quantity 1 > Quantity 2 B) Quantity 1 ≥ Quantity 2
C) Quantity 1 < Quantity 2 D) Quantity 1 ≤ Quantity 2

Answer:   A) Quantity 1 > Quantity 2



Explanation:

Quantity 1:
Let the first pipe alone takes x hours to fill the
tank.
⇒The second and third pipes will take (x-5) and
(x-9) hours respectively.
According to the given information:
∴ 1x-9

⇒ (x-9)(2x-5) = x2 – 5x
⇒ 2x2 – 5x – 18x + 45 = x2 – 5x
⇒ x
2 -18x + 45 = 0
⇒ (x-15) (x-3) = 0
⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.
∵ 3 hours doesn’t satisfy the statement.
Quantity 2:
∴ Time taken by second pipe = x-5
⇒ Time taken by second pipe = 15-5 = 10hours
∴ Time taken by third pipe = x -9
⇒ Time taken by third pipe = 15- 9 = 6 hours
Now,

Net part filled in 1 hour = 115+110+16
⇒ Net part filled in 1 hour = 4+6+1060
⇒Net part filled in 1 hour = 2060=13
∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously
Now, comparing
15 > 3
Thus, Quantity 1 > quantity 2

Q:

Bob Kashir deposited $6000 in a 4-year certificate of deposite paying 5% compounded daily.He withdrew the money 15 months later.The passbook rate at his bank is 3.5 % compounded daily.Find his amount of interest

A) 5678 B) 4563
C) 4329 D) 6210.73
 
Answer & Explanation Answer: D) 6210.73

Explanation:

Bob receives 15-3 = 12 months of 3.5 % interest compounded daily

 

 

 

M=P(1+i/365)^365n

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0 2792
Q:

Find the compound amount if $1200 is deposited at 8% interest for 11 years if interest is compounded continuously

A) 1456 B) 1456
C) 1693.08 D) 1890
 
Answer & Explanation Answer: C) 1693.08

Explanation:

M=Pe^yr

 

2893.08

 

I=M-P

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0 2559
Q:

Find the compound amount if $2900 is deposited at 5% interest for 10 years if interest is compounded daily

A) 4781.13 B) 5781
C) 3456 D) 4567
 
Answer & Explanation Answer: A) 4781.13

Explanation:

M=P(1+i/365)^365n

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0 2274
Q:

$32000 is invested at 10% for 2 years.Find the interest compounded Yearly

A) 4720 B) 5720
C) 6720 D) 7720
 
Answer & Explanation Answer: C) 6720

Explanation:

M=P(1+i)^n

 

I=M-P

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0 2098
Q:

Example:$800 is invested at 7% for 6 years.Find the interest compounded anually?

A) 400.58 B) 300.58
C) 200.58 D) 100.58
 
Answer & Explanation Answer: A) 400.58

Explanation:

M=P(1+i)^n

 

I=M-P

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0 2523
Q:

Dianna deposits $725 into a savings account that pays 2.3% simple annual interest. How much interest will Dianna earn after 18 months?

A) 23.01 B) 24.01
C) 25.01 D) 26.01
 
Answer & Explanation Answer: C) 25.01

Explanation:

I = Prt

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0 3423
Q:

A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interst. The rate per annum 

A) 5% B) 5.5%
C) 6% D) 6.5%
 
Answer & Explanation Answer: B) 5.5%

Explanation:

sum = x. amount =7x/6.

S.I. =(7x/6 – x) = x/6 ; time = 3 years

Rate =[ (100 * x) / (x * 6 * 3)]% = 5.5%

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18 22390
Q:

If a sum of money at simple interest doubles in 6 years, it will become  4 times in

A) 15years B) 16years
C) 17years D) 18years
 
Answer & Explanation Answer: D) 18years

Explanation:

 

 

 

 

 

 

let sum =x . s.i.=x

 

 

 

rate =(100*x)/(x*6)=50/3%

 

 

 

now ,sum =x, s.i= 3x, rate =50/3%

 

 

 

time =(100*3x)/(x*50/3) = 18 years

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