A) 360, 160, 200 | B) 160, 360, 200 |

C) 200, 360,160 | D) 200,160,300 |

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

A) 154 | B) 135 |

C) 112 | D) 106 |

Explanation:

From the given data,

Virat : Rohit = 3 : 2

Rohit : Dhoni = 3 : 2

Ratio of runs scored by Virat, Rohit and Dhoni respectively

= 3 x 3 : 2 x 3 : 2 x 2

9 : 6 : 4

Runs scored by Virat =** 9/19 x 285 = 135.**

A) 10 lit | B) 6 lit |

C) 16 lit | D) 12 lit |

Explanation:

Given ratio of initial mixture of milk and water in Q = 5 : 3

Let the initial quantity of mixture in vessel Q = 8x

Let quantity of Milk = 5x and

Let quantity of water = 3x

According to the question,

$\frac{\mathbf{5}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{10}\mathbf{}\mathbf{x}\mathbf{}{\displaystyle \frac{\mathbf{3}}{\mathbf{5}}}}{\mathbf{3}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{10}\mathbf{}\mathbf{x}\mathbf{}{\displaystyle \frac{\mathbf{2}}{\mathbf{5}}}\mathbf{}}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{8}}{\mathbf{5}}$

=> 25x + 30 = 24x + 32

=> x = 2

Required Initial quantity of milk = 5x = 5 x 2 = 10 lit.

A) Rs. 1600 | B) Rs. 1700 |

C) Rs. 1800 | D) Rs. 1900 |

Explanation:

Let the salaries of Maneela and Shanthi one year before be **M1, S1** & now be **M2, S2** respectively.

Then, from the given data,

M1/S1 = 3/4 .....(1)

M1/M2 = 4/5 .....(2)

S1/S2 = 2/3 .....(3)

and M2 + S2 = 4160 .....(4)

Solving all these eqtns, we get M2 = Rs. 1600.

A) 444 | B) 344 |

C) 244 | D) 144 |

Explanation:

Given ratio of pens and pencils = 3 :2

Number of Pens = 3x

Number of Pencils = 2x

Average number of pencils & Pens = $\frac{\mathbf{3}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{2}\mathbf{x}}{\mathbf{2}}\mathbf{}\mathbf{=}$ 180

5x = 360

=> x = 72

Hence, the number of pencils **= 2x = 72 x 2 = 144.**

A) 17 | B) 30 |

C) 26 | D) 32 |

Explanation:

$3\phantom{\rule{0ex}{0ex}}{3}^{2}+3=12\phantom{\rule{0ex}{0ex}}5\phantom{\rule{0ex}{0ex}}{\mathbf{5}}^{\mathbf{2}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{5}\mathbf{}\mathbf{=}\mathbf{}\mathbf{30}$

A) 6548 | B) 5667 |

C) 7556 | D) 8457 |

Explanation:

Let ratio of the incomes of Pavan and Amar be 4x and 3x

and Ratio of their expenditures be 3y and 2y

4x - 3y = 1889 ......... I

and

3x - 2y = 1889 ...........II

I and II

y = 1889

and x = 1889

**Pavan's income = 7556**

A) 7:1 | B) 13:5 |

C) 15:7 | D) 2:7 |