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Q:

Session_End: occurs when the users stop requesting pages and their session times out.

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

True.It occurs when the user stops requsting pages and session time is out

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Subject: .NET
Job Role: Software Architect

Q:

Session_Start: This event occurs every time when any new user visits.

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

True .That event occurs whenever a new user visits

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Subject: .NET
Job Role: Software Architect

Q:

Application_End: This event occurs when there are no more users of the application.

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

When there are no more users of the application Application_End event occurs

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Subject: .NET
Job Role: Software Architect

Q:

Application_Start: This event occurs when the first user visits a page of the application.

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

whenever user visits a page application Application_start event occurs

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Subject: .NET
Job Role: Software Architect

Q:

if $\log_{10} 5 + \log (5 x + 1) = \log_{10} (x + 5) + 1, t h e n x i s e q u a l t o$

A) 1	B) 3
C) 5	D) 10

Answer & Explanation Answer: B) 3

Explanation:

$\log_{10} 5 + \log (5 x + 1) = \log_{10} (x + 5) + 1$

$\log_{10} [5 (5 x + 1)] = \log_{10} [10 (x + 5)]$

$5 (5 x + 1) = 10 (x + 5)$

5x+1=2x+10

3x=9

x=3

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Who is the author of the book "The Judgement"?

A) Kuldip Nayar	B) Mathili Saran Gupta
C) Amitabh Ghosh	D) None

Answer & Explanation Answer: A) Kuldip Nayar

Explanation:

Kuldip Nayar is the author of "The Judgement"

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Filed Under: Books and Authors

Q:

What annual payment will discharge a debt of Rs.7620 due in 3years at $16 \frac{2}{3}$ % per annum interest?

A) 5430	B) 4430
C) 3430	D) 2430

Answer & Explanation Answer: C) 3430

Explanation:

Let each installment be Rs.x. Then,

(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.

$[\frac{x}{(1 + \frac{50}{3 x 100})}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{2}}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{3}}] = 7620$

$\frac{6 x}{7} + \frac{36 x}{49} + \frac{216 x}{343} = 7620$

$294 x + 252 x + 216 x = 7620 x 343$

=> x = 3430

Amount of each installment = Rs.3430

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If the compound interest on a certain sum at $16 \frac{2}{3}$ % to 3 years is Rs.1270, find the simple interest on the same sum at the same rate and f or the same period.

A) 1080	B) 1090
C) 1180	D) 1109

Answer & Explanation Answer: A) 1080

Explanation:

Let the sum be Rs. x. Then,

$C . I = [x * {(\frac{50}{300 * 100})}^{3} - x] = (\frac{343 x}{216} - x) = \frac{127 x}{216}$

$\Leftrightarrow \frac{127 x}{216} = 1270$

$x = 2160$

Thus, the sum is Rs. 2160

$S . I = R s . [2160 * \frac{50}{3} * 3 * \frac{1}{100}] = R s 1080$

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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