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Q:

If log 2 = 0.3010 and log 3 = 0.4771, the values of log5 512 is

A) 2.875 B) 3.875
C) 4.875 D) 5.875
 
Answer & Explanation Answer: B) 3.875

Explanation:

ANS:      log5512 = log512/log5  =  log29log10/2  =9log2log10-log2 =9*0.30101-0.3010 =2.709/0.699 =2709/699 =3.876

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Q:

A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?

A) 156 B) 166
C) 176 D) 186
 
Answer & Explanation Answer: C) 176

Explanation:

Area of the room=(544 * 374)

 

size of largest square tile= H.C.F of 544 & 374 = 34 cm

 

Area of 1 tile = (34  x  34) cm2

 

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

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Q:

The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?

A) 10cm B) 20cm
C) 30cm D) 40cm
 
Answer & Explanation Answer: B) 20cm

Explanation:

Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is 2x2

 

 

 

after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)=2x2+5x-25

since new area is 75 units greater than original area thus
2x2+75 = 2x+5x-25
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.

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Q:

A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?

A) 56m B) 65m
C) 34m D) 36m
 
Answer & Explanation Answer: A) 56m

Explanation:

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

 

Hence number of poles required = 280 / 5 = 56

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Q:

The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.

A) Rs.15500 B) Rs.16500
C) Rs.17500 D) Rs.18500
 
Answer & Explanation Answer: B) Rs.16500

Explanation:

Area = 5.5 × 3.75 sq. metre.

Cost for 1 sq. metre. = Rs. 800

 

Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500

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Q:

2 metres broad pathway is to be constructed around a rectangular plot on the inside. The area of the plots is 96 sq.m. The rate of construction is Rs. 50 per square metre. Find the total cost of the construction?

A) 20 B) 30
C) 40 D) data is inadequate
 
Answer & Explanation Answer: D) data is inadequate

Explanation:

Given lb =96

Area of pathway = [(l-4)(b-4)-lb] = 16-4(l+b)

Which cannot be determined. so, data is inadequate.

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Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20 B) 200
C) 300 D) 400
 
Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40]  * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters. 

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Q:

The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 sq.m. The length of the hall is

A) 20 B) 25
C) 30 D) 35
 
Answer & Explanation Answer: C) 30

Explanation:

Let breadth = x m

 

Then, length = (x+5)m

 

Area of a rectangle = Length x Breadth

 

x(x+5) = 750 

 

x² + 5x - 750= 0

 

(x+30)(x-25)= 0

 

x = 25 or x = -30

 

Hence, breadth x = 25m

 

=> Length = x + 5 = 25 + 5 = 30m. 

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