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Q:

Find the cash realised by selling Rs. 2440, 9.5% stock at 4 discount (brokerage 1/4 %)

A) 2000	B) 2298
C) 2290	D) 2289

Answer & Explanation Answer: B) 2298

Explanation:

By selling Rs. 100 stock , cash realised = $R s . [(100 - 4) - \frac{1}{4}] = R s . \frac{383}{4}$

By selling Rs. 2400 stock, cash realised = $R s . (\frac{383}{4} * \frac{1}{100} * 2400)$ = Rs 2298.

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Q:

Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are black or both are queen?

A) 52/221	B) 55/190
C) 55/221	D) 19/221

Answer & Explanation Answer: C) 55/221

Explanation:

We have n(s) = $52 C_{2}$ 52 = 52*51/2*1= 1326.

Let A = event of getting both black cards

B = event of getting both queens

A∩B = event of getting queen of black cards

n(A) = $\frac{52 * 51}{2 * 1}$ = $26 C_{2}$ = 325, n(B)= $\frac{26 * 25}{2 * 1}$ = 4*3/2*1= 6 and n(A∩B) = $4 C_{2}$ = 1

P(A) = n(A)/n(S) = 325/1326;

P(B) = n(B)/n(S) = 6/1326 and

P(A∩B) = n(A∩B)/n(S) = 1/1326

P(A∪B) = P(A) + P(B) - P(A∩B) = (325+6-1) / 1326 = 330/1326 = 55/221

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Q:

Find the annual income derived from Rs. 2500, 8% stock at 106?

A) 100	B) 200
C) 150	D) 250

Answer & Explanation Answer: B) 200

Explanation:

Income from Rs. 100 stock = Rs. 8.

Income from Rs. 2500 stock = $R s (\frac{8}{100} * 2500)$ = Rs. 200.

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Q:

Find the cost of Rs. 6400, 10% stock at 15 discount?

A) 2000	B) 5440
C) 6000	D) 5140

Answer & Explanation Answer: B) 5440

Explanation:

Cost of Rs. 100 stock = Rs. (100-15)

Cost of Rs. 6400 stock = $R s . \frac{85}{100} * 6400$ = Rs. 5440.

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Q:

Find the cost of Rs. 4500, 8.5% stock at 4 premium?

A) 1400	B) 5000
C) 4000	D) 4680

Answer & Explanation Answer: D) 4680

Explanation:

Cost of Rs. 100 stock = Rs. (100+4) = Rs.104

Cost of Rs. 4500 stock = $R s . \frac{104}{100} \times 4500$ = Rs. 4680

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Q:

One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.

A) 1/3	B) 1/2
C) 1/4	D) 1/6

Answer & Explanation Answer: B) 1/2

Explanation:

Total number of elementary events = 52

There are 26 red cards,out of which one red card can be drawn in $26 C_{1}$ ways =26.

So,required probability = 26/52 = 1/2

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Q:

A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A) 551/15134	B) 1/2
C) 552/15379	D) 1/9

Answer & Explanation Answer: A) 551/15134

Explanation:

Total number of elementary events = $50 C_{5}$
Given,third ticket =30

=> first and second should come from tickets numbered 1 to 29 = $29 C_{2}$ ways and remaining two in $20 C_{2}$ ways.

Therfore,favourable number of events = $29 C_{2} * 20 C_{2}$

Hence,required probability = $29 C_{2} * 20 C_{2}$ $/ 50 C_{5}$ =551 / 15134

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Q:

A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?

A) 13/42	B) 17/42
C) 5/42	D) 3/14

Answer & Explanation Answer: B) 17/42

Explanation:

3 letters can be choosen out of 9 letters in $9 C_{3}$ ways.

More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in $(4 C_{2} * 5 C_{1}) + 4 C_{3}$ ways

Hence,required probability = $\frac{(4 C_{2} * 5 C_{1}) + 4 C_{3}}{9 C_{3}}$ = 17/42

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