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Q:

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

Quantity I: The Sl on a certain sum of money for 3 years at 5% per annum is Rs 4800. Then the principle is?

Quantity II: The Cl on a certain sum of money for 2 years at 6% per annum is Rs. 3708. Then the principle is?

A) Quantity I > Quantity II	B) Quantity I ≥ Quantity II
C) Quantity I < Quantity II	D) Quantity I < Quantity II

Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:

Quantity I=15% of Principle=4800

Principle=Rs.32000

Quantity II=12.36% of Principle =3708

Principle=Rs.30000

Hence Quantity I > Quantity II

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Filed Under: Simple Interest

Q:

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

Quantity I: Vipin can swim at 6 km/hr in still water. The river flows at 3 km/hr and it takes 8 hours more upstream then downstream for the same distance. How far is the place?

Quantity II: A man can row 25 km/hr in still water and the river is running at 15 km/hr. if the man takes 2 hr to row to a place and back, how far is the place?

A) Quantity I > Quantity II	B) Quantity I ≥ Quantity II
C) Quantity I < Quantity II	D) Quantity I < Quantity II

Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:

Quantity I: let d be the distance covered ATQ d/(6-3)-d/(6+3)=8 d=36km

Quantity II: ATQ d/(25-15)+d/(25+15)=2 D=16km

Hence Quantity I > Quantity II

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Filed Under: Time and Distance

Q:

In the question, two equations I and II are given. You have to solve both the equations and give answer

$x^{2} - 11 x + 28 = 0 y^{2} - 18 y + 81 = 0$

A) x > y	B) x < y
C) x=y, or relation cannot be established between x and y	D) x ≥ y

Answer & Explanation Answer: B) x < y

Explanation:

x2 – 11x + 28=0

x2 – 7x – 4x + 28=0

x (x-7) – 4 (x-7)=0

(x-4) (x-7)=0 x=4, 7

y2 – 18y + 81=0

y2 –9y – 9y + 81=0

y (y-9) – 9 (y-9)=0

(y-9) (y-9)=0 y=9, 9

So, x<y.

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Filed Under: Simplification

Q:

In each of these questions, two equations (I) and (II) are given.

$I . 2 x^{2} + 19 x + 42 = 0 II . 4 y^{2} + 43 y + 30 = 0$

A) x > y	B) x < y
C) x ≥ y	D) x ≤ y

Answer & Explanation Answer:

Explanation:

I. 2x2 + 19x + 42 = 0

2x2 + 12x + 7x + 42 = 0

2x (x+6) + 7(x +6) = 0

(2x+7) (x+6) = 0 x = -7/2, -6 I

I. 4y2 + 43y + 30 = 0

4y2 +40y + 3y + 30 = 0

4y(y + 10) + 3(y + 10) (4y + 3)(y + 10) = 0

y = -3/4, -10

So answer is no relation.

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Filed Under: Simplification

Q:

In each of the following questions two equations I and II are given. Solve both the equations and give answer:
$I . x^{2} + 2 x - 195 = 0 II . y^{2} + 30 y + 225 = 0$

A) x = y or relation can’t be established between x and y	B) x > y
C) x < y	D) x ≥ y

Answer & Explanation Answer: D) x ≥ y

Explanation:

I. x2 + 2x - 195 = 0 = (x+15) (x-13) => x = -15, 13

II. y2 + 30y + 225 = 0 = (y+15) (y+15) => y = -15, -15

So x ≥ y

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Filed Under: Simplification

Q:

In the question given below, two equations are provided. Solve the equations and establish the relationship between x and y

$I . 2 x^{2} - 13 x - 189 = 0 II . 2 y^{2} - 3 y - 189 = 0$

A) x>y	B) x≥y
C) x<y	D) x≤y

Answer & Explanation Answer:

Explanation:

I. 2x2 - 13x - 189 = 0 2x2 - 27x + 14x - 189 = 0 x(2x - 27) + 7(2x - 27) = 0 x = -7, 27/2

II. 2y2 - 3y - 189 = 0 2y2 - 21y + 18y - 189 = 0 y(2y - 21) + 9(2y - 21) = 0 y = -9, 21/2

When x, as well as y, have both positive and negative values then no relationship can be established between them because if we consider x to be positive then the negative value of y will be lesser than x. If we consider x to be negative then positive value of y will be greater than x.

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Filed Under: Simplification

Q:

Two number P & Q are 20 % and 28 % less then a number X. What is the percentage the number Q is smaller then the number P?

A) 10%	B) 23%
C) 12%	D) 13%

Answer & Explanation Answer: A) 10%

Explanation:

Let the number X is 100

Then, PÃ 80 QÃ 72

So, Percentage decrease from P to Q is Ã 8/80=0.1-100=10%

1 is the right choice.

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Filed Under: Percentage

Q:

The ages of Sunil and Anil are in the ratio 8:7, after 6 years, the ratio of their ages will be 19 : 17. What is the difference in their present ages?

A) 10 years	B) 6 years
C) 8 years	D) 4 years

Answer & Explanation Answer: D) 4 years

Explanation:

suppose the ages of Sunil and Anil are 8x yr and 7x yr, respectively.
After 6 yr, = 136x + 102 = 133x + 114
136x – 133x = 114 – 102
3x = 12 X = 12/3 = 4
Age of Sunil = 8x = 8 × 4 = 32 yr
Present age Anil = 7x = 7 × 4 = 28 yr
Required difference = (32 – 28) = 4 yr

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Filed Under: Problems on Ages
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