and Search

Q:

Two letters are randomly chosen from the word TIME. Find the probability that the letters are T and M?

A) 1/4	B) 1/6
C) 1/8	D) 4

Answer & Explanation Answer: B) 1/6

Explanation:

Required probability is given by P(E) = $\frac{n (E)}{n (S)} = \frac{1}{4 C_{2}} = \frac{1}{6}$

Report Error

View Answer Report Error Discuss

Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

Q:

6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally?

A) 38	B) 72
C) 36	D) 76

Answer & Explanation Answer: C) 36

Explanation:

Given 4men, 12 women and 20 children work for 2 days.

Workdone for 2 days by 4men, 12 women and 20 children = $\frac{4 x 2}{6 x 12} + \frac{12 x 2}{8 x 18} + \frac{20 x 2}{18 x 10} = \frac{1}{2}$

Therefore, remaining work = 1 - $\frac{1}{2}$ = $\frac{1}{2}$

To complete the same work by only men in 1 day,

We know that M1 x D1 = M2 x D2

Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1

12 x 6 = M x 1

=> M = 12 x 6 = 72

=> But the remaining work = 1/2

Men required => 1/2 x 72 = 36

Only men required to Complete the remaining work in 1 day = 36.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Q:

A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey?

A) 32 kmph	B) 20 kmph
C) 18 kmph	D) 24 kmph

Answer & Explanation Answer: D) 24 kmph

Explanation:

Let the total distance of the journey of a man = d kms

Now, the average speed of the entire journey = $\frac{d}{\frac{d}{120} + \frac{d}{120} + \frac{d}{40}}$ = 24 kmph.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

Q:

Poison glands of snakes are homologous to

A) sebaceous glands of mammals	B) salivary glands of vertebrates
C) stings of rays	D) electric organs of fishes

Answer & Explanation Answer: B) salivary glands of vertebrates

Explanation:

Here Homologous Means having the same relation or relative position or structure.

Here in snakes poison is in glands and here salivary glands are in Vertebrates.

Report Error

View Answer Report Error Discuss

Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Q:

There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number?

A) 29	B) 27
C) 31	D) 33

Answer & Explanation Answer: A) 29

Explanation:

Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4

According to the question,

Difference between square of the average of first two odd number and the of the average last

two odd numbers is 396

i.e, x+3 and x-3

$\Rightarrow {(x + 3)}^{2} - {(x - 3)}^{2} = 396 \Rightarrow x^{2} + 9 + 6 x - x^{2} + 6 x - 9 = 396 \Rightarrow 12 x = 396 \Rightarrow x = 33$

Hence, the smallest odd number is 33 - 4 = 29.

Report Error

View Answer Report Error Discuss

Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Q:

Durand Cup is associated with the game of

A) Badminton	B) Volleyball
C) Football	D) Hockey

Answer & Explanation Answer: C) Football

Explanation:

Durand Cup is associated with the game of Football.

Durand_Cup_is_associated_with_the_game_of1556278989.jpg image

The Durand Football Tournament or Durand Cup is a football competition in India which was first held in 1888. This competition was named after its founder, Sir Mortimer Durand from Simla.

Report Error

View Answer Report Error Discuss

Filed Under: Honours and Awards
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: IT Trainer , Database Administration , Bank PO , Bank Clerk , Analyst

Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm	B) 50 gm
C) 55 gm	D) 60 gm

Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper = $\frac{80}{100} x 50$ = 40 g

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> $(50 + p) x \frac{90}{100}$ = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Q:

In order to maximize his gain, a shopping mall owner decides to reduce the price of electronics goods by 20% and as a result of this, the sales of electronics increase by 40%. If, as a result of these changes, he is able to increase his weekly collection by Rs. 1,05,000, find by what value did the gross collection increase per day?

A) Rs. 14400	B) Rs. 14600
C) Rs. 14800	D) Rs. 15000

Answer & Explanation Answer: D) Rs. 15000

Explanation:

It won't requires that much solving.

Here given the increase in weekly collection by Rs. 1,05,000

That is this increase denotes for all 7 days.

=> Gross Collection increase per day = $\frac{Rs . 1, 05, 000}{7} = Rs . 15, 000$

Hence, the gross collection increase per day = Rs. 15,000.

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Searching for "and"

Quick Links