Ho Search

Q:

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is :

A) 2/9	B) 1/9
C) 8/9	D) 7/9

Answer & Explanation Answer: B) 1/9

Explanation:

One person can select one house out of 3= $3 C_{1}$ ways =3.

Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9.

Therefore, probability that all thre apply for the same house is 1/9

Report Error

View Answer Report Error Discuss

Filed Under: Probability

Q:

There are six persons A. B, C, D, E and F. C is the sister of F. B is the brother of E's husband. D is the father of A and grandfather of F. There are two fathers, three brothers and a mother in the group. Who is the mother ?

A) A	B) B
C) C	D) E

Answer & Explanation Answer: D) E

Explanation:

D is father of A and grandfather of F. So, A is father of F.

Thus. D and A are the two fathers. C is the sister of F So. C is the daughter of A.

Since there is only one mother, it is evident that E is the wife of A and hence the mother of C and F.

So, B is brother of A There are three brothers. So. F is the brother of C.

Clearly, A is E's Husband.

Report Error

View Answer Report Error Discuss

Filed Under: Blood Relations

Q:

I. A. B, C. D, E and F are six members of a family.

II. One couple has parents and their children in the family.

III. A is the son of C and E is the daughter of A.

IV. D is the daughter of F who is the mother of E.

Which of the following pairs is the parents of the couple ?

A) AB	B) BC
C) AF	D) CF

Answer & Explanation Answer: B) BC

Explanation:

E is the daughter of A and F is the mother of E So, A is the father of E and hence the husband of F. Now,

D is the daughter of F So. D and E are the daughters of A and F Also. A is the son of C.

Now, only B remains Thus. B and C are the parents of A.

Clearly. B and C are the parents of the couple

Report Error

View Answer Report Error Discuss

Filed Under: Blood Relations

Q:

E is the son of A. D is the son of B. E is married to C. C is B's daughter. How is D related to E ?

A) Brother	B) Uncle
C) Father-in-Law	D) Brother-in-law

Answer & Explanation Answer: D) Brother-in-law

Explanation:

C is D's daughter and D is B's son. So, D is the brother of C. E is a male married to C.

So, E is the husband of C, whose brother is D. So, D is the brother-in-law of E.

Report Error

View Answer Report Error Discuss

Filed Under: Blood Relations

Q:

Find the area of a square, one of whose diagonals is 3.8 m long.

A) 4.22 sq.m	B) 5.22 sq.m
C) 6.22 sq.m	D) 7.22 sq.m

Answer & Explanation Answer: D) 7.22 sq.m

Explanation:

Area of the square = $\frac{1}{2} \times {(d i a g o n a l)}^{2}$ = 1/2 * 3.8 * 3.8 = 7.22 sq.m

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Find the probability of selecting 2 woman when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.

A) 1/5	B) 1/7
C) 1/6	D) 1/9

Answer & Explanation Answer: C) 1/6

Explanation:

Out of 9 persons,4 can be choosen in $9 C_{4}$ ways =126.

Favourable events for given condition = $2 C_{2} * 7 C_{2}$ = 21.

So,required probability = 21/126 =1/6.

Report Error

View Answer Report Error Discuss

Filed Under: Probability

Q:

A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?

A) 13/42	B) 17/42
C) 5/42	D) 3/14

Answer & Explanation Answer: B) 17/42

Explanation:

3 letters can be choosen out of 9 letters in $9 C_{3}$ ways.

More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in $(4 C_{2} * 5 C_{1}) + 4 C_{3}$ ways

Hence,required probability = $\frac{(4 C_{2} * 5 C_{1}) + 4 C_{3}}{9 C_{3}}$ = 17/42

Report Error

View Answer Report Error Discuss

Filed Under: Probability

Q:

Find the probability of selecting exactly 2 children when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.

A) 9/29	B) 10/21
C) 12/21	D) 14/19

Answer & Explanation Answer: B) 10/21

Explanation:

4 persons can be selected from 9 in $9 C_{4}$ ways =126

Fvaourable events = $4 C_{2} * 5 C_{2}$ =60

So,required probability = 60/126 = 10/21

Report Error

View Answer Report Error Discuss

Filed Under: Probability

Searching for "Ho"

Quick Links