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Q:

Ajay bought 15 kg of dal at the rate of Rs 14.50 per kg and 10 kg at the rate of Rs 13 per kg. He mixed the two and sold the mixture at the rate of Rs 15 per kg. What was his total gain in this transaction ?

A) Rs 1.10	B) Rs 11
C) Rs 16.50	D) Rs 27.50

Answer & Explanation Answer: D) Rs 27.50

Explanation:

Cost price of 25 kg = Rs. (15 x 14.50 + 10 x 13) = Rs. 347.50.
Sell price of 25 kg = Rs. (25 x 15) = Rs. 375.
profit = Rs. (375 — 347.50) = Rs. 27.50.

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Filed Under: Profit and Loss

Q:

Tea worth of Rs. 135/kg & Rs. 126/kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be____?

A) Rs. 169.50	B) Rs.1700
C) Rs. 175.50	D) Rs. 180

Answer & Explanation Answer: C) Rs. 175.50

Explanation:

Since first second varieties are mixed in equal proportions, so their average price = Rs.(126+135)/2= Rs.130.50

So, Now the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say Rs. 'x' per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find 'x'.

Cost of 1 kg tea of 1st kind Cost of 1 kg tea of 2nd kind

x-153/22.50 = 1 => x - 153 = 22.50 => x=175.50.

Hence, price of the third variety = Rs.175.50 per kg.

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Filed Under: Alligation or Mixture
Exam Prep: CAT , Bank Exams , AIEEE

Q:

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

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Subject: Table Charts

Q:

Study the following table and answer the questions based on it. Expenditures of a Company (in Pesetas) per Annum Over the given Years.

1. What is the average amount of interest per year which the company had to pay during this period?

A. 32.43 B. 33.72 C. 34.18 D. 36.66

2. The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?

A. 0.1% B. 0.5% C. 1.0% D. 1.25 %

3. Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?

A. 62% B. 66% C. 69% D. 71%

4. The total expenditure of the company over these items during the year 2000 is?

A. 544.44 B. 501.11 C. 446.46 D. 478.87

5. The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?

A. 4 : 7 B. 10 : 13 C. 15 : 18 D. 5 : 8

The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

The total expenditure of the company over these items during the year 2000 is? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

0.1%

What is the average amount of interest per year which the company had to pay during this period? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

Answer

1. ANSWER : D

Explanation -

Average amount of interest paid by the company during the given period

= $R s . \frac{23.4 + 32.5 + 41.6 + 36.4 + 49.4}{5} l a k h s = R s . \frac{183.3}{5} l a k h s$

= Rs. 36.66 lakhs

2. ANSWER : C

Explanation -

Required Percentage = $\frac{3.00 + 2.52 + 3.84 + 3.68 + 3.96}{288 + 342 + 324 + 336 + 420} \times 100$ %

= $\frac{17}{1710} \times 100$ % $\approx$ 1%

3. ANSWER: C

Explanation -

Required Percentage = $\frac{288 + 98 + 3.00 + 23.4 + 83}{420 + 142 + 3.96 + 49.4 + 98} \times 100$

= $\frac{495.4}{713.36} \times 100$ $\approx$ 69.45%

4. ANSWER: A

Explanation - Total expenditure of the Company during 2000 = (324 + 101 + 3.84 + 41.6 + 74) lakhs = 544.44 lakhs

5. ANSWER : B

Explanation -

Required ratio = $\frac{83 + 108 + 74 + 88 + 98}{98 + 112 + 101 + 133 + 142}$

= $\frac{451}{586}$

= $\frac{1}{1.3} = \frac{10}{13}$

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Subject: Table Charts

Q:

Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies ove the Years (Number in Thousands)

1. What is the difference between the number of vehicles manufactured by Company Y in 2000 and 2001 ?

A. 50000 B. 42000 C. 33000 D. 21000

2. What is the difference between the total productions of the two Companies in the given years ?

A. 19000 B. 22000 C. 26000 D. 28000

3. What is the average numbers of vehicles manufactured by Company X over the given period ? (rounded off to nearest integer)

A. 119333 B. 113666 C. 112778 D. 111223

4. In which of the following years, the difference between the productions of Companies X and Y was the maximum among the given years ?

A. 1997 B. 1998 C. 1999 D. 2000

5. The production of Company Y in 2000 was approximately what percent of the production of Company X in the same year ?

A. 173 B. 164 C. 132 D. 97

Answer

1. ANSWERS : D

Explanation- Required difference = (128000 - 107000) = 21000.

2. ANSWERS : C

Explanation- From the line-graph it is clear that the productions of Company X in the years 1997, 1998, 1999, 2000, 2001 and 2002 are 119000, 99000, 141000, 78000, 120000 and 159000 and those of Company Y are 139000, 120000,100000, 128000, 107000 and 148000 respectively.

Total production of Company X from 1997 to 2002

= 119000 + 99000 + 141000 + 78000 + 120000 + 159000

= 716000.

and total production of Company Y from 1997 to 2002

= 139000 + 120000 + 100000 + 128000 + 107000 + 148000

= 742000.

Difference = (742000 - 716000) = 26000.

3. ANSWERS : A

Explanation- Average number of vehicles manufactured by Company X

= $\frac{1}{6} \times (119000 + 99000 + 141000 + 78000 + 120000 + 159000)$

= 119333.

4. ANSWERS : D

Explanation- The difference between the productions of Companies X and Y in various years are:

For 1997 (139000 - 119000) = 20000.

For 1998 (120000 - 99000) = 21000.

For 1999 (141000 - 100000) = 41000.

For 2000 (128000 - 78000) = 50000.

For 2001 (120000 - 107000) = 13000.

For 2002 (159000 - 148000) = 11000.

Clearly, maximum difference was in 2000.

5. ANSWERS : B

Explanation - Required percentage= $\frac{128000}{78000} \times 100$ % = 164%

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Subject: Line Charts

Q:

Your network contains an application server named Server1 that runs Windows Server 2003 Service Pack(SP2). You open the Performance tab in Task Manager as shown in the exhibit:

You need to improve the performance of Server1. What should you do?

A) Install additional RAM.	B) Install a second processor.
C) Decrease the size of the paging file.	D) Add the /PAE switch to the Boot.ini file.

Answer & Explanation Answer: A) Install additional RAM.

Explanation:

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Filed Under: MCSA-Microsoft Certified Solutions Associate

Q:

After the devices have been configured as shown, it is determined that the branch office in Chicago doesn't have connectivity to the Internet through the headquarters in Dallas. How would you fix the problem?

A) Change ip address on the WAN side of the Chicago router	B) Change ip address on the LAN side of the Chicago router
C) Change ip address on the LAN side of the Dallas router	D) Change ip address on the WAN side of the Dallas router

Answer & Explanation Answer: A) Change ip address on the WAN side of the Chicago router

Explanation:

192.168.20.3/30 is not a valid ip address, should be 192.168.20.1/30

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Filed Under: CCENT

Q:

Assume a router has a loopback address of 135.77.9.254. Convert the loopback address to an IS-IS system ID.

Answer

The loopback address written in dotted decimal and using three digits for each byte has a value of 135.077.009.254. The system ID is 13.50.77.00.92.54.

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Subject: CCNP

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