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Q:

Find out from amongst the four alternatives as to how the pattern would appear when the transparent sheet is folded at the dotted line.

(X) (1) (2) (3) (4)

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: D) 4

Explanation:

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Filed Under: Paper Folding

Q:

Find out from amongst the four alternatives as to how the pattern would appear when the transparent sheet is folded at the dotted line.

(X) (1) (2) (3) (4)

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: D) 4

Explanation:

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Filed Under: Paper Folding

Q:

On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?

A) Sunday	B) Monday
C) Tuesday	D) Wednesday

Answer & Explanation Answer: C) Tuesday

Explanation:

The year 1985 is an ordinary year. So, it has 1 odd day.

So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.

But, 19th June,1984 is Monday

S0, 19th June, 1985 is Tuesday.

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Filed Under: Calendar

Q:

If $a^{2} = 12, t h e n a^{4} = ?$

A) 144	B) 72
C) 36	D) 24

Answer & Explanation Answer: A) 144

Explanation:

Given a x a = 12

asked to find a x a x a x a = (a x a) x (a x a)

a⁴ = a² x a²

= 12 x 12

= 144.

More :: Mathematical operations questions and answers.

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Filed Under: Numbers
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Q:

In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys?

A) 15	B) 10
C) 25	D) 20

Answer & Explanation Answer: C) 25

Explanation:

The toys are different; The boxes are identical
If none of the boxes is to remain empty, then we can pack the toys in one of the following ways
a. 2,2,1
b. 3,1,1

Case a. Number of ways of achieving the first option 2−2–1

Two toys out of the 5 can be selected in $5 C_{2}$ 5 ways. Another 2 out of the remaining 3 can be selected in $3 C_{2}$ ways and the last toy can be selected in $1 C_{1}$ way.

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2.

Therefore, total number of ways of achieving the 2−2–1 option is:

$\frac{5 C_{2} * 3 C_{2}}{2} = \frac{10 * 3}{2} = 15$ ways.

Case b. Number of ways of achieving the second option 3−1–1

Three toys out of the 5 can be selected in $5 C_{3}$ ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.
Therefore, total number of ways of getting the 3−1–1 option is $5 C_{3}$ =10 ways.

Total ways in which the 5 toys can be packed in 3 identical boxes
=number of ways of achieving Case a + number of ways of achieving Case b
=15 + 10 = 25 ways

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Filed Under: Permutations and Combinations

Q:

Who is the author of the book "The Judgement"?

A) Kuldip Nayar	B) Mathili Saran Gupta
C) Amitabh Ghosh	D) None

Answer & Explanation Answer: A) Kuldip Nayar

Explanation:

Kuldip Nayar is the author of "The Judgement"

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Filed Under: Books and Authors

Q:

In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize ?

A) 1/7	B) 2/7
C) 3/7	D) 2/5

Answer & Explanation Answer: B) 2/7

Explanation:

P(getting prize) = 10/ (10 + 25) =2/7

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Filed Under: Probability

Q:

The value of $(\frac{1}{\log_{3} 60} + \frac{1}{\log_{4} 60} + \frac{1}{\log_{5} 60}) i s$

A) 0	B) 1
C) 5	D) 60

Answer & Explanation Answer: B) 1

Explanation:

=> $\log_{60} (3 * 4 * 5)$

=> $\log_{60} (60)$

= 1

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Filed Under: Logarithms
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Job Role: Bank PO

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