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Q:

What approximate value should come in place of the question mark (?) in the following equation (Note: You are not expected to calculate the exact value)?(55.01+16.0003)×22.01÷10.998 =?

A) 190 B) 130
C) 110 D) 142
 
Answer & Explanation Answer: D) 142

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

Q:

What approximate value should come in place of the question mark (?) in the following equation (Note: You are not expected to calculate the exact value)? √580×∛510+ 49.999 x 3.999=?

A) 384 B) 392
C) 410 D) 372
 
Answer & Explanation Answer: B) 392

Explanation:

Take nearest values
√580×∛510+ 49.999 x 3.999=?
24x 8 + 200 = 392

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Filed Under: Simplification
Exam Prep: Bank Exams
Job Role: Bank PO , Bank Clerk

Q:

In the given questions, two equations numbered I and II are given. Solve both the equation and mark the appropriate answer

I. x2=529  II. y =529

A) x>y B) x≥y
C) x<y D) x≤y
 
Answer & Explanation Answer: D) x≤y

Explanation:

x = ±23

And, y = 23

hence, x ≤ y

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Filed Under: Statement and Conclusions
Exam Prep: Bank Exams , CAT
Job Role: Bank Clerk

Q:

In the following questions two equations numbered I and II are given. You have to solve boththe equations and give answers

I. 2x ² –21x + 54 = 0

II. y ² –14y + 49 = 0

A) x = y or relation can’t be established between x and y B) x > y
C) x < y D) x ≥ y
 
Answer & Explanation Answer: C) x < y

Explanation:

I. 2x ² –21x + 54 = 0(x -6)(2x -9)x =+6, +9/2

II. y ² –14y + 49 = 0(y-7) (y-7)y = +7, +7y > x

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Filed Under: Simplification
Exam Prep: Bank Exams

Q:

In each question two equations numbered I and II are given,you haveto solve both the equation and choose the correctanswer.

I. x2+ 30x + 81 = 0

II.y2-9y -162 = 0

A) x > y B) x>y
C) x < y D) x
 
Answer & Explanation Answer:

Explanation:

x^2+ 30x + 81 = 0
x^2+ 27x + 3x + 81 = 0
x = -3, -27
y^2-9y -162 = 0
y^2-18y + 9y -162 = 0
y = -9, 18
Hence, no relationship can be established between x and y

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Filed Under: Simplification
Exam Prep: Bank Exams
Job Role: Bank PO , Bank Clerk

Q:

In each question two equations numbered I and II are given,you haveto solve both the equation and choose the correctanswer.

I. 5x2+ 28x = -15II. 3y2+ 11y + 6 = 0

A) X > Y B) X ≥ Y
C) X < Y D) X ≤ Y
 
Answer & Explanation Answer:

Explanation:

5x^2+ 28x = -15x = (-3/5, -5)

II. 3y^2+ 11y + 6 = 0y = (-3, -2/3)

So Relationship cannot be established

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

Both S.I. and C.I. is calculated with a similar rate of 10% per annum on a sum of rupees. If C.I. is calculated yearly for two years, then for what period must S.I. be evaluated such that S.I. = C.I.?

A) 4.2 years B) 2.1 years
C) 1.1 years D) 1.4 years
 
Answer & Explanation Answer: B) 2.1 years

Explanation:

Let time period of S.I. be T years.

Then for a principal amount, say P,

ATQ, as, S.I. = C.I. for rate =10%p.a. and

time for C.I. = 2(P x 10 x T)/100 = P{[ (100+10)/100 ]2-1}T/10 = [ 110/100 ]2–1 = [(11/10)2–1] = (121-100)/100T/10 = 21/100T = 21/10 = 2.1 years

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO , Bank Clerk

Q:

What will come in place of the question marks (?) in the following Number series?8, 14, 26, 44, 68 (?)

A) 94 B) 102
C) 96 D) 98
 
Answer & Explanation Answer: D) 98

Explanation:

The pattern is + 6, + 12, + 18, +24 ...........So the missing term is = 68 +30 = 98

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Filed Under: Number Series