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Q:

A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at $6 \frac{1}{4}$ p.a for 2 years. Find his gain in the transaction per year

A) Rs. 112.50	B) Rs.150.25
C) Rs.167.50	D) Rs.170

Answer & Explanation Answer: A) Rs. 112.50

Explanation:

$g a i n i n 2 y e a r s = R s . [(5000 * \frac{25}{4} * \frac{2}{100}) - (\frac{5000 * 4 * 2}{100})]$

= Rs. (625 - 400)

= Rs. 225

$g a i n i n 1 y e a r = R s . (\frac{225}{2}) = 112.50$

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is:

A) 5%	B) 8%
C) 12%	D) 15%

Answer & Explanation Answer: C) 12%

Explanation:

S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.

S.I. for 5 years = Rs. $\frac{2205}{3} \times 5$ = Rs.3675

Principle = Rs.(9800-3675) = Rs.6125

Hence, Rate = $[\frac{100 \times 3675}{6125 \times 5}]$ =12%

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:

A) Rs.2000	B) Rs.10000
C) Rs.15000	D) Rs.20000

Answer & Explanation Answer: C) Rs.15000

Explanation:

Principal = $R s (\frac{100 \times 5400}{12 \times 3}) = R s . 15000$

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

How does the browser know to go to a certain IP address When you enter a domain like google.com?

Answer

When we enter a URL such as google.com then It searches through local DNS cache, if nothing is there, it queries the ISP's DNS server to resolve the URL.

Workspace

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Subject: Hardware

Q:

If the mean of a, b, c is M and ab + bc + ca = 0, then the mean of $\frac{a^{2} + b^{2} + c^{2}}{3}$ is :

A) M	B) 3 M^2
C) 2 (M/3)	D) M^2

Answer & Explanation Answer: B) 3 M^2

Explanation:

We have : ( a + b + c) / 3 = M or (a + b + c) = 3M.

Now. ${(a + b + c)}^{2} = {(3 M)}^{2} = 9 M^{2}$ .

$< = > a^{2} + b^{2} + c^{2} + 2 (a b + b c + c a) = 9 M^{2}$

$a^{2} + b^{2} + c^{2} = 9 M^{2}, (a b + b c + c a = 0)$

Required mean = $(\frac{a^{2} + b^{2} + c^{2}}{3}) = \frac{9 M^{2}}{3} = 3 M^{2}$ .

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

What are the rules to use the ROWGUIDCOL property to define a globally unique identifier column?

Answer

Only one column can exist per table that is attached with ROWGUIDCOL property. One can then use $ROWGUID instead of column name in select list.

Workspace

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Subject: SQL

Q:

A, B, C, D and E are sitting in a row. B is between A and K Who among them is in the middle ?

I. A is left of 13 and right of D.

II.C is at the right end.

A) If the data in statement I alone are sufficient to answer the question	B) If the data in statement II alone are sufficient answer the question
C) If the data either in I or II alone are sufficient to answer the question;	D) If the data in both the statements together are needed.

Answer & Explanation Answer: D) If the data in both the statements together are needed.

Explanation:

Clearly, we have the order : A. a E. From I, we have the order : D, A, B. E.

From II, we get the complete sequence as D, A, B. E, C.

Clearly. B is in the middle. So, both I and II are required.

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Filed Under: Data Sufficiency

Q:

The current birth rate per thousand is 32, whereas corresponding death rate is 11 per thousand. The net growth rate in terms of population increase in percent is given by :

A) 1.2 %	B) 2.1 %
C) 3.1 %	D) 1.3 %

Answer & Explanation Answer: B) 2.1 %

Explanation:

Net growth on 1000 = (32 - 11) = 21. Net growth on 100 =(21/1000 * 100) %= 2.1%.

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Filed Under: Percentage

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