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Q:

The amount of simple interest accrued on an amount of Rs 28,500 in seven years is Rs 23,940 What is the rate of interest p.c.p.a ?

A) 10.5 B) 12.5
C) 11 D) 12
 
Answer & Explanation Answer: D) 12

Explanation:

Simple Interest = S.I= pnr/100 Given, S.I = 23940 , p = 28500 , n = 7 thus, r = 100x23940/28500x7 = 12

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Filed Under: Simple Interest

Q:

Ravi invested Rs.P in a scheme A offering simple interest at 10% p.a. for two years. He invested the whole amount he received from scheme A, in another scheme (B) offering simple interest at 12% p.a. for five years. If the difference between the interests earned from schemes A and B was Rs. 13,00/, what is the value of P ?

A) 2500 B) 2000
C) 3000 D) 3500
 
Answer & Explanation Answer: A) 2500

Explanation:

It is given that the initial amount invested in scheme A is Rs P at 10%per Annum S.I. =PTR/100 = P x 10 x 2/100 Now the total amount after 2 years is = 1.2P New Rate of interest = 12% per annum Time = 5 years S.I for next 5 years when new principal amount is 1.2 P = 1.2Px12x5/100 = 0.72P Total amount after 5 years at 12% per annun = 1.72P Given that 1.72P - 1.2P = 1300 P = 1300/0.52 P = Rs. 2500

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Filed Under: Simple Interest

Q:

Who amongst the following Wrestlers has been the recipient of the Rajiv Gandhi Khel Ratna Award?

A) Vijender Singh B) Sushil Kumar
C) Anand Kumar Singh D) Zoravar Singh Faujdar
 
Answer & Explanation Answer: B) Sushil Kumar

Explanation:
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Filed Under: Sports

Q:

Savita sold an item for 6,500 and incurred a loss of 20%. At what price should she have sold the item to have gained a profit of 20%?

A) 10,375 B) 9,750
C) 8,125 D) Cannot be determined
 
Answer & Explanation Answer: B) 9,750

Explanation:

C.P of article = 6500 * (100/80) = Rs. 8125 S.P for a gain of 20% = (8125*120)/100 = Rs. 9750

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Filed Under: Profit and Loss

Q:

Jar A has 36 litres of mixture of milk and water in the respective ratio of 5 : 4. Jar B which had 20 litres of mixture of milk and water, was emptied into jar A, and as a result in jar A, the respective ratio of milk and water becomes 5: 3. What was the quantity of water in jar B?

A) 5 lit B) 3 lit
C) 8 lit D) 2 lit
 
Answer & Explanation Answer: A) 5 lit

Explanation:

Jar A has 36 litres of mixture of milk and water in the respective ratio of 5 : 4 => Quantity of milk in Jar A = 5/9 x 36 = 20 litres Quantity of water in Jar A = 36 - 20 = 16 litres Let quantity of water in Jar B = x litres => Quantity of milk in Jar B = (20 - x) litres Acc. to ques, =>[20 + (20-x)]/(16+x) = 5/3 => 120−3x = 80+5x => 5x +3x = 120−80 => 8x = 40 => 5 litres.

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Filed Under: Alligation or Mixture

Q:

Three friends J, K and L jog around a circular stadium and complete one round in 12, 18 and 20 seconds respectively. In how many minutes will all the three meet again at the starting point.

A) 5 B) 8
C) 12 D) 3
 
Answer & Explanation Answer: D) 3

Explanation:

All the three friends will meet at the starting point again after X seconds, such that X is the LCM of the times taken by J, K and L to complete one round.

=> LCM of 12, 18 and 20 = 180 seconds = 3 minutes.

Hence 3 minutes is the answer.

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Filed Under: HCF and LCM

Q:

What will come in place of the question mark (?) in the given question?

120 % of 750 ÷ 25 - 16 = ? % of 1240 ÷ 31

A) 25 B) 30
C) 20 D) 45
 
Answer & Explanation Answer:

Explanation:

120 % of 750 ÷ 25 - 16 = ? % of 1240 ÷ 31 ? = 50

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Filed Under: Number Series

Q:

What will come in place of the question mark (?) in the given question?

1.5 % of 4600 + 2.8% of 2000 - 109 = ?

A) 32 B) 28
C) 12 D) 16
 
Answer & Explanation Answer: D) 16

Explanation:

1.5 % of 4600 + 2.8% of 2000 - 109 = ? ? = 16

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Filed Under: Number Series