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Q:

Prove that any date in March of a year is the same day of the week corresponding date in November that year.

A) Same day B) Not same day
C) Next day D) Previous day
 
Answer & Explanation Answer: A) Same day

Explanation:

We will show that the number of odd days between last day of February and last day of October is zero. .

March April May June July Aug. Sept. Oct.

31 + 30 + 31 + 30 + 31 + 31 + 30 + 31

= 241 days = 35 weeks = 0 odd day. ,Number of odd days during this period = 0.

Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows

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Filed Under: Calendar

Q:

Which of the following year is a leap year?

A) 2500 B) 1700
C) 1900 D) 2400
 
Answer & Explanation Answer: D) 2400

Explanation:

NOTE: For a century year,it is divided by 400 and leaving a ramainder of 0 results a leap year.

So,2400 when divided by 400 leaves a remainder 0.

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Q:

Which of the following years have 366 days?

A) 1984 B) 1863
C) 1900 D) 2500
 
Answer & Explanation Answer: A) 1984

Explanation:

NOTE: When an year leaves a remainder 0 when divided by 4,then it is a leap year.

Here, 1984 divided by 4 leaves a remainder 0.

So, answer 1984 (366 days => leap year)

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Q:

From the following years,which is not a leap year ?

A) 1996 B) 1984
C) 1863 D) 2004
 
Answer & Explanation Answer: C) 1863

Explanation:

NOTE: When a year leaves a remainder 0 when divided by 4,then it is a leap year.

Here, 1863 divided by 4 doesnot give a remainder 0.

So, 1863 is not a leap year.

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Q:

A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?

A) 56m B) 65m
C) 34m D) 36m
 
Answer & Explanation Answer: A) 56m

Explanation:

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

 

Hence number of poles required = 280 / 5 = 56

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.

A) Rs.15500 B) Rs.16500
C) Rs.17500 D) Rs.18500
 
Answer & Explanation Answer: B) Rs.16500

Explanation:

Area = 5.5 × 3.75 sq. metre.

Cost for 1 sq. metre. = Rs. 800

 

Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is

A) 64% B) 74%
C) 84% D) 94%
 
Answer & Explanation Answer: A) 64%

Explanation:

Area of the sheet = 20×30cm2  

Area used for typing = 20-4×30-6cm2   

required % =384600×100=64%

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?

A) 44ft B) 88ft
C) 22ft D) 11ft
 
Answer & Explanation Answer: B) 88ft

Explanation:

Given that length and area, so we can find the breadth.

 Length  x  Breadth = Area 

 => 20  x  Breadth = 680 

=> Breadth = 34 feet 

Area to be fenced = 2B + L = 2 (34) + 20 = 88 feet

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO