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Q:

Two dice are tossed. The probability that the total score is a prime number is :

A) 1/6	B) 1/2
C) 5/12	D) 3/4

Answer & Explanation Answer: C) 5/12

Explanation:

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Filed Under: Probability

Q:

A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:

A) 0%	B) 5%
C) 7.5%	D) 10%

Answer & Explanation Answer: A) 0%

Explanation:

C.P = Rs.3000

S.P =Rs. [3600 x 10] / [100+(10 x 2)] = Rs.3000

Gain =0%

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Filed Under: True Discount

Q:

The probabilities that drivers A, B and C will drive home safely after consuming liquor are 2 / 5, 3 / 7 and 3 / 4, respectively. What is the probability that they will drive home safely after consuming liquor ?

A) 3/70	B) 4/70
C) 9/70	D) 1/50

Answer & Explanation Answer: C) 9/70

Explanation:

Let A be the event of driver A drive safely after consuming liquor.

Let B be the event of driver B drive safely after consuming liquor.

Let C be the event of driver C drive safely after consuming liquor.

P(A)=2/5,P(B)=3/7,P(C)=3/4

The events A, B and C are independent . Therefore,

$P (A \cap B \cap C) = P (A) P (B) P (C) = \frac{2}{5} * \frac{3}{7} * \frac{3}{4} = \frac{9}{70}$

Therefore, The probability that all the drivers will drive home safely after consuming liquor is 9/70

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Filed Under: Probability

Q:

The odds favouring the event of a person hitting a target are 3 to 5. The odds against the event of another person hitting the target are 3 to 2. If each of them fire once at the target, find the probability that both of them hit the target.

A) 1/20	B) 4/20
C) 1/20	D) 3/20

Answer & Explanation Answer: D) 3/20

Explanation:

Let A be the event of first person hitting the target,

$P (A) = \frac{3}{3 + 5} = \frac{3}{8} (o d d i n f a v o u r)$

Let B be the event of Second person hitting a target.

$P (B) = \frac{2}{3 + 2} = \frac{2}{5} (o d d a g a i n s t)$

Since both events are independent and both will hit the target so,

$P (A \cap B) = P (A) P (B) = \frac{3}{8} \times \frac{2}{5} = \frac{3}{20}$

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Filed Under: Probability

Q:

Course materials are sent to students by a distance teaching institution. The probability that they will send a wrong programme’s study material is 1/5. There is a probability of 3/4 that the package is damaged in transit, and there is a probability of 1/3 that there is a short shipment. What is the probability that the complete material for the course arrives without any damage in transit?

A) 4/5	B) 2/3
C) 1/2	D) 2/15

Answer & Explanation Answer: D) 2/15

Explanation:

Probability of sending the correct material is 4/5

Probability of the material not being damaged in transit is 1/4

Probability that there is no short shipment = 2/3

∴ Required probability =4/5 x 1/4 x 2/3 = 2/15

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Filed Under: Quantitative Aptitude - Arithmetic Ability

Q:

Which of the following statements is not correct?

A) log10 = 1	B) log (2 + 3) = log (2 x 3)
C) log1 = 0	D) log (1 + 2 + 3) = log 1 + log 2 + log 3

Answer & Explanation Answer: B) log (2 + 3) = log (2 x 3)

Explanation:

log (2 + 3) = log 5

log (2 x 3) = log 2 + log 3

log (2 + 3) $\neq$ log (2 x 3)

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A cube of edge 15 cm is immersed completely in a rectangular vessel containing water . If the dimensions of the base of vessel are 20 cm x 15 cm, find the rise in water level

A) 11.25cm	B) 11.56cm
C) 11.66cm	D) 10.86cm

Answer & Explanation Answer: A) 11.25cm

Explanation:

Increase in volume = Volume of the cube = (15 x 15 x 15) cm3.

\Rise in water level = volume/area = (15 x 15 x 15)/(20 x 15) cm = 11.25 cm.

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Filed Under: Quantitative Aptitude - Arithmetic Ability

Q:

Find the number of bricks, each measuring 24 cm x 12 cm x 8 cm, required to construct a wall 24 m long, 8m high and 60 cm thick, if 10% of the wall is filled with mortar?

A) 35000	B) 45000
C) 55000	D) 65000

Answer & Explanation Answer: B) 45000

Explanation:

Volume of the wall = (2400 x 800 x 60) cu.cm

Volume of bricks = 90% of the volume of the wall

= [(90/100) x 2400 x 800 x 60] cu.cm

Volume of 1 brick = (24 x 12 x 8) cu.cm

Number of bricks = [(90/100) x (2400 x 800 x 60) ]/ (24 x 12 x 8) = 45000

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Filed Under: Volume and Surface Area

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