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Q:

A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a

king of heart is:

A) 2/13	B) 1/13
C) 1/26	D) 1/52

Answer & Explanation Answer: C) 1/26

Explanation:

Here, n(S) = 52.

Let E = event of getting a queen of club or a king of heart.

Then, n(E) = 2.

P(E) =n(E)/n(S)=2/52=1/26.

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Filed Under: Probability

Q:

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A) 1/15	B) 1/221
C) 25/57	D) 35/256

Answer & Explanation Answer: B) 1/221

Explanation:

Let S be the sample space

Then, n(S) = $52 C_{2}$ = 1326.

Let E = event of getting 2 kings out of 4.

n(E) = $\frac{52 * 51}{2 * 1}$ = 6.

$4 C_{2}$

=> $\frac{4 * 3}{2 * 1}$

$P (E) = \frac{n (E)}{n (S)} = \frac{6}{1326} = \frac{1}{221}$

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Q:

In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?

A) 2/7	B) 5/7
C) 1/5	D) 1/2

Answer & Explanation Answer: A) 2/7

Explanation:

Total number of outcomes possible, n(S) = 10 + 25 = 35

Total number of prizes, n(E) = 10

$P (E) = \frac{n (E)}{n (S)} = \frac{10}{35} = \frac{2}{7}$

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Filed Under: Probability

Q:

Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?

A) 3/4	B) 3/8
C) 5/16	D) 2/7

Answer & Explanation Answer: A) 3/4

Explanation:

In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3,4),(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

n(E) = 27.

P(E) = n(E)/n(S) = 27/36 = 3/4.

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Q:

Three unbiased coins are tossed. What is the probability of getting at most two heads?

A) 3/4	B) 7/8
C) 1/2	D) 1/4

Answer & Explanation Answer: B) 7/8

Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) =n(E)/n(S)=7/8.

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Q:

What is the probability of getting a sum 9 from two throws of a dice?

A) 1/2	B) 3/4
C) 1/9	D) 2/9

Answer & Explanation Answer: C) 1/9

Explanation:

In two throws of a die, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) =n(E)/n(S)=4/36=1/9.

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Q:

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to be repaid if he is repaying the entire amount at the end of 2 years?

I. The rate of interest is 5 p.c.p.a.

II. Simple interest fetched on the same amount in one year is Rs. 600.

III. The amount borrowed is 10 times the simple interest in 2 years.

A) I only	B) III only
C) I or II only	D) .II and Either I or III only

Answer & Explanation Answer: D) .II and Either I or III only

Explanation:

I. gives, Rate = 5% p.a.

II. gives, S.I. for 1 year = Rs. 600.

III. gives, sum = 10 x (S.I. for 2 years).

Now I, and II give the sum.

For this sum, C.I. and hence amount can be obtained.

Thus, III is redundant.

Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.

Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.

Thus, Rate =

100 x 1200

= 5% p.a.

2 x 12000

Thus, C.I. for 2 years and therefore, amount can be obtained.

Thus, I is redundant.

Hence, I or III redundant.

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to
be repaid if he is repaying the entire amount at the end of 2 years?
I. The rate of interest is 5 p.c.p.a.
II. Simple interest fetched on the same amount in one year is Rs. 600.
III. The amount borrowed is 10 times the simple interest in 2 years.

A) .I only	B) III only
C) I or II	D) II and Either I or III only

Answer & Explanation Answer: D) II and Either I or III only

Explanation:

I. gives, Rate = 5% p.a.

II. gives, S.I. for 1 year = Rs. 600.

III. gives, sum = 10 x (S.I. for 2 years).

Now I, and II give the sum.

For this sum, C.I. and hence amount can be obtained.

Thus, III is redundant.

Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.

Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.

Thus,Rate = $\frac{100 * 1200}{2 * 12000}$ =5%

Thus, C.I. for 2 years and therefore, amount can be obtained.

Thus, I is redundant.

Hence, I or III redundan

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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