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Q:

This statesman,politican,scholar,inventor,and one of early presidents of USA invented the swivel chair,the spherical sundial,the moldboard plow,and the cipher wheel.

A) George Washington	B) Alexander Hamilton
C) John Adams	D) Thomas Jefferson

Answer & Explanation Answer: D) Thomas Jefferson

Explanation:

Thomas Jefferson (April 13, 1743 – July 4, 1826) was the third President of the United States (1801-1809) and the principal author of the Declaration of Independence (1776).

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Filed Under: Inventions

Q:

Which of the following parts of the sun is easily visible only during a total solar eclipse?

A) core	B) photosphere
C) sunspots	D) corona

Answer & Explanation Answer: D) corona

Explanation:

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Filed Under: General Science

Q:

If × stands for 'addition', ÷ stands for 'subtraction', + stands for 'multiplication' and-stands for 'division', then 20 × 8 ÷ 8 - 4 + 2 = ?

A) 80	B) 25
C) 24	D) 5

Answer & Explanation Answer: C) 24

Explanation:

By the Given data , We have the expression:

20 + 8 - 8 ÷ 4 × 2 = 20 + 8 - 2 × 2 = 20 + 8 - 4 = 24.

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Filed Under: Mathematical Operations

Q:

In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?

A) 20	B) 25
C) 30	D) Data inadequate

Answer & Explanation Answer: C) 30

Explanation:

Let the number of boys and girls participating in sports be 3x and 2x respectively.

Then, 3x = 15 or x = 5.

So, number of girls participating in sports = 2x = 10.

Number of students not participating in sports = 60 - (15 + 10) = 35.

Let number of boys not participating in sports be y.

Then, number of girls not participating in sports = (35 -y).

Therefore (35 - y) = y + 5 <=> 2y<=> 30<=> y = 15.

So, number of girls not participating in sports = (35 - 15) = 20.

Hence, total number of girls in the class = (10 + 20) = 30.

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Filed Under: Arithmetical Reasoning

Q:

Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

A) 10 min. 20 sec.	B) 11 min. 45 sec.
C) 12 min. 30 sec.	D) 14 min. 40 sec.

Answer & Explanation Answer: D) 14 min. 40 sec.

Explanation:

Part filled in 4 minutes =4(1/15+1/20) = 7/15

Remaining part =(1-7/15) = 8/15

Part filled by B in 1 minute =1/20 : 8/15 :: 1:x

x = (8/15*1*20) = $10 \frac{2}{3} m i n = 10 m i n 40 s e c$

The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec

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Filed Under: Pipes and Cistern

Q:

Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:

A) 60 gallons	B) 100 gallons
C) 120 gallons	D) 180 gallons

Answer & Explanation Answer: C) 120 gallons

Explanation:

Work done by the waste pipe in 1 minute = $\frac{1}{15} - (\frac{1}{20} + \frac{1}{24}) = \frac{1}{15} - \frac{11}{120} = - \frac{1}{40}$ [-ve sign means emptying]

Volume of $\frac{1}{40}$ part = 3 gallons

Volume of whole = (3 x 40) gallons = 120 gallons.

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

A) 10	B) 12
C) 14	D) 16

Answer & Explanation Answer: C) 14

Explanation:

Part filled in 2 hours = 2/6=1/3

Remaining part = $(1 - \frac{1}{3}) = \frac{2}{3}$

(A + B)'s 7 hour's work = 2/3

(A + B)'s 1 hour's work = 2/21

C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }

=1/6-2/21 = 1/14

C alone can fill the tank in 14 hours.

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Filed Under: Pipes and Cistern

Q:

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:

A) 173 m	B) 200 m
C) 273 m	D) 300 m

Answer & Explanation Answer: C) 273 m

Explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100m, $∠ A C B = 30 ° a n d ∠ A D B = 45 °$

$\frac{A B}{A C} = \tan 30 ° = \frac{1}{\sqrt{3}} = > A C = A B * \sqrt{3} = 100 \sqrt{3 m}$

$\frac{A B}{A D} = \tan 45 ° = 1 = > A D = A B = 100 m$

CD=(AC+AD)= $(100 \sqrt{3} + 100) m = 100 (\sqrt{3} + 1) = 100 * 2.73 = 273 m$

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Filed Under: Height and Distance

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