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Q:

Application_Start: This event occurs when the first user visits a page of the application.

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

whenever user visits a page application Application_start event occurs

Workspace

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Subject: .NET
Job Role: Software Architect

Q:

Sharon Stone deposits $500 at the beginning of each 3 months in an account earning 10% compounded quarterly. Determine how much money she has after 25 years

A) 22681.19	B) 23456
C) 44577	D) 25685

Answer & Explanation Answer: A) 22681.19

Explanation:

S=R[(1+i)^n-1)/i]

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The true discount on a bill due 9 months hence at 12% per annum is Rs. Find the amount of the bill and its present worth.

A) 1500	B) 1600
C) 6200	D) 6000

Answer & Explanation Answer: D) 6000

Explanation:

Let amount be Rs. x.

Then, [X * R * T] / [100+(R * T)]

$\Rightarrow \frac{x \times 12 \times \frac{3}{4}}{100 + (12 \times \frac{3}{4})} = 540$

x= Rs.6540

Amount = Rs. 6540.

P.W. = Rs. (6540 – 540) =Rs. 6000.

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Filed Under: True Discount

Q:

A three-digit number is formed with the digits 1, 2, 3, 4, 5 at random. What is probability that number formed is divisible by 5 ?

A) 1/4	B) 1/5
C) 1/2	D) 3/4

Answer & Explanation Answer: B) 1/5

Explanation:

If a number ends with 5, 0 then the number will be divisible by 5
Here only 5 is present, end place will be fixed by 5 so,

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Filed Under: Probability

Q:

If each edge of a cube is increased by 50%, find the percentage increase in Its surface area

A) 125%	B) 150%
C) 175%	D) 110%

Answer & Explanation Answer: A) 125%

Explanation:

Let the edge = a cm

So increase by 50 % = a + a/2 = 3a/2

Total surface Area of original cube = $6 a^{2}$

TSA of new cube = $6 {(\frac{3 a}{2})}^{2}$ = $6 (\frac{9 a^{2}}{4})$ = $13.5 a^{2}$

Increase in area = $13.5 a^{2} - 6 a^{2}$ = $7.5 a^{2}$

$7.5 a^{2}$ Increase % = $\frac{7.5 a^{2}}{6 a^{2}} \times 100$ = 125%

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Filed Under: Volume and Surface Area

Q:

The surface area of a cube is 1734 sq. cm. Find its volume

A) 2334 cubic.cm	B) 3356 cubic.cm
C) 4913 cubic.cm	D) 3478 cubic.cm

Answer & Explanation Answer: C) 4913 cubic.cm

Explanation:

Let the edge of the cube bea. Then,

6 $a^{2}$ = 1734

=> a = 17 cm.

Volume = $a^{3}$ = $17^{3}$ = 4193 cu.cm

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Filed Under: Volume and Surface Area

Q:

The diagonal of a cube is $6 \sqrt{3}$ cm. Find its surface area

A) 216 sq.cm	B) 316 sq.cm
C) 416 sq.cm	D) 516 sq.cm

Answer & Explanation Answer: A) 216 sq.cm

Explanation:

Let the edge of the cube be a.

so, the diagonal a $\sqrt{3}$ = $6 \sqrt{3}$

=> a=6

Surface area = $6 a^{2}$ = 6 x 6 x 6 = 216 sq.cm

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Filed Under: Volume and Surface Area

Q:

The dimensions of an open box are 50 cm, 40 cm and 23 cm. Its thickness is 2 cm. If 1 cubic cm of metal used in the box weighs 0.5 gms, find the weight of the box.

A) 8.04kg	B) 8.14kg
C) 8.24kg	D) 9.04kg

Answer & Explanation Answer: A) 8.04kg

Explanation:

Volume of the metal used in the box = External Volume - Internal Volume

= [(50 x 40 x 23) - (44 x 34 x 20)] cu.cm

= 16080 cu.cm

Weight of the metal =[(16080 x 0.5)/1000] kg = 8.04 kg.

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Filed Under: Volume and Surface Area

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