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Q:

In a class, 30% of the students offered English, 20% offered Hindi and 10% offered both. If a student is selected at random, what is the probability that he. has offered English or Hindi ?

A) 1/2	B) 3/4
C) 4/5	D) 2/5

Answer & Explanation Answer: D) 2/5

Explanation:

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Filed Under: Probability

Q:

Two dice are tossed. The probability that the total score is a prime number is :

A) 1/6	B) 1/2
C) 5/12	D) 3/4

Answer & Explanation Answer: C) 5/12

Explanation:

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Filed Under: Probability

Q:

A man and his wife appear in an interview for two vacancies in the same post. The probability of husband's selection is (1/7) and the probability of wife's selection is (1/5). What is the probability that only one of them is selected ?

A) 2/7	B) 1/7
C) 3/4	D) 4/5

Answer & Explanation Answer: A) 2/7

Explanation:

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Filed Under: Probability

Q:

A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:

A) 0%	B) 5%
C) 7.5%	D) 10%

Answer & Explanation Answer: A) 0%

Explanation:

C.P = Rs.3000

S.P =Rs. [3600 x 10] / [100+(10 x 2)] = Rs.3000

Gain =0%

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Filed Under: True Discount

Q:

A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:

A) gains Rs. 55	B) gains Rs. 50
C) loses Rs. 30	D) gains Rs. 30

Answer & Explanation Answer: B) gains Rs. 50

Explanation:

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Filed Under: True Discount

Q:

The odds favouring the event of a person hitting a target are 3 to 5. The odds against the event of another person hitting the target are 3 to 2. If each of them fire once at the target, find the probability that both of them hit the target.

A) 1/20	B) 4/20
C) 1/20	D) 3/20

Answer & Explanation Answer: D) 3/20

Explanation:

Let A be the event of first person hitting the target,

$P (A) = \frac{3}{3 + 5} = \frac{3}{8} (o d d i n f a v o u r)$

Let B be the event of Second person hitting a target.

$P (B) = \frac{2}{3 + 2} = \frac{2}{5} (o d d a g a i n s t)$

Since both events are independent and both will hit the target so,

$P (A \cap B) = P (A) P (B) = \frac{3}{8} \times \frac{2}{5} = \frac{3}{20}$

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Filed Under: Probability

Q:

The letters of the word CASTIGATION is arranged in different ways randomly. What is the chance that vowels occupy the even places ?

A) 0.04	B) 0.043
C) 0.047	D) 0.05

Answer & Explanation Answer: B) 0.043

Explanation:

Vowels are A I A I O,

C A S T I G A T I O N

(O) (E) (O) (E) (O) (E) (O) (E) (O) (E) (O)

So there are 5 even places in which five vowels can be arranged and in rest of 6 places 6 constants can be arranged as follows :

$n (E) = \frac{5 P_{5}}{2! * 2! (A, I a r e 2 t i m e s)} * \frac{6 P_{6}}{2! (T i s 2 t i m e s)} = 21600$

$n (S) = \frac{11!}{2! * 2! * 2! (A, I a r e 2 t i m e s)} = 4989600$

$\frac{21600}{4989600} = 0.043$

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Filed Under: Probability
Exam Prep: GRE

Q:

Course materials are sent to students by a distance teaching institution. The probability that they will send a wrong programme’s study material is 1/5. There is a probability of 3/4 that the package is damaged in transit, and there is a probability of 1/3 that there is a short shipment. What is the probability that the complete material for the course arrives without any damage in transit?

A) 4/5	B) 2/3
C) 1/2	D) 2/15

Answer & Explanation Answer: D) 2/15

Explanation:

Probability of sending the correct material is 4/5

Probability of the material not being damaged in transit is 1/4

Probability that there is no short shipment = 2/3

∴ Required probability =4/5 x 1/4 x 2/3 = 2/15

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Filed Under: Quantitative Aptitude - Arithmetic Ability

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