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Q:

The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?

A) 62 degrees B) 64 degrees
C) 65 degrees D) 66 degrees
 
Answer & Explanation Answer: B) 64 degrees

Explanation:

Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)

Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees  ....(2)

Subtracting (1) From (2), we get :

Temp, on 5th day  - Temp on 1st day  = 8 degrees.

Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.

Then, 8x - 7x = 8 or x = 8.

Temperature on the 5th day = 8x = 64 degrees.

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Filed Under: Average

Q:

The average of 11 numbers is 10.9. If the average of the first six numbers is 10.5 and that of the last six numbers is 11.4, then the middle number is :

A) 10.5 B) 11.5
C) 12.5 D) 13.5
 
Answer & Explanation Answer: B) 11.5

Explanation:

Middle numbers  =  [(10.5 x 6 + 11.4 x 6) - 10.9 x 11] = (131.4 - 119-9) = 11.5.

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Filed Under: Average

Q:

The average age of the boys in a class is 16 years and that of the girls is 15 years. The average age for the whole class is :

A) 15 B) 20
C) 21 D) data inadequate
 
Answer & Explanation Answer: D) data inadequate

Explanation:

 Clearly, to find the average, we ought to know the number of boys, girls or students in the class, neither of which has been given.

So, the data provided is inadequate.

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Filed Under: Average

Q:

The average of the two-digit numbers, which remain the same when the dibits inter-change their positions, is :

A) 53 B) 54
C) 55 D) 56
 
Answer & Explanation Answer: C) 55

Explanation:

Average = (11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99) / 9

             =( (11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55) / 9

             = (4 * 110 + 55)/9 =  495 / 9 = 55. 

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Filed Under: Average

Q:

16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B ?

A) 233/3 B) 243/4
C) 254/5 D) 345/7
 
Answer & Explanation Answer: A) 233/3

Explanation:

 Required average = [(76 * 16) - (75 * 10)] / 6 = (1216 - 750)/6 = 466/3 = 233 /3.

 

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Filed Under: Average

Q:

Suppose you have a computional circuit between two registers driven by a clock. What will you do if the delay of the combinational circuit is greater than your clock signal?

Answer

Use the concept of register-retiming.


divide the totla combinatorial delay in two segments such that individually the delay is less the clock period.


this can be done by inserting a flip-flop in the combinational path.


e.g.,


clock period --- 5 ns


total cominational delay ---- 7


then divide the 7ns path in two path of 4 or 3 (best resutls are obtained if delays are  same for both path i.e 3.5ns) by inserting a flip-flop in between.

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Subject: Hardware

Q:

A motorist travels to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/hr.  His average speed for the whole journey in km/hr is :

A) 35 B) 36
C) 37.5 D) 38.2
 
Answer & Explanation Answer: C) 37.5

Explanation:

Average speed = (2xy) /(x + y) km/hr

                      = (2 * 50 * 30) / (50 + 30) km/hr.

                         37.5 km/hr.

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Filed Under: Average

Q:

Draw a Transmission Gate-based D-Latch?

Answer

The Transmission-Gate's input is connected to the D_LATCH data input (D), the control input to the Transmission-Gate is connected to the D-Latch enable inputs (EN) and the Transmission-Gate outputs is the D_LATCH output(Q)

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Subject: Hardware