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Q:

Out of 9 persons, 8 persons spent Rs. 30 each for their meals. The ninth one spent Rs. 20 more than the average expenditure of all the nine. The total money spent by all of them was : 

A) Rs. 292.50 B) Rs. 297.50
C) Rs. 298 D) Rs. 298.50
 
Answer & Explanation Answer: A) Rs. 292.50

Explanation:

Let the average expenditure be Rs. x Then,

 

9x=[(8*30)+(x+20)]<=>9x =x+260 <=> x =32.50

 

Total money spent = 9x =  Rs. (9 x 32.5O) = Rs 292. 50

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Q:

A team of 8 persons joins in a shooting competition. The best marksman scored 85 points. If he had scored 92 points, the average score for the team would have been 84. The number of points, the team scored was :

A) 665 B) 657
C) 658 D) 678
 
Answer & Explanation Answer: A) 665

Explanation:

Let the total score be x.

(x + 92 - 85) / 8 = 84.

So,  x + 7 = 672   => x = 665.

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Q:

The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

A) 35 B) 36.5
C) 40 D) 42
 
Answer & Explanation Answer: B) 36.5

Explanation:

Correct Sum = (36 * 50 + 48 - 23) = 1825.

Correct mean = = 1825/50 = 36.5

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Q:

If the mean of a, b, c is M and ab + bc + ca = 0, then the mean of a2+b2+c23 is :

A) M B) 3 M^2
C) 2 (M/3) D) M^2
 
Answer & Explanation Answer: B) 3 M^2

Explanation:

We have : ( a + b + c) / 3 = M   or (a + b + c) = 3M.

Now. a+b+c2=3M2=9M2 .

 

 

 

<=>a2+b2+c2+2ab+bc+ca=9M2

 

 

 

a2+b2+c2=9M2   ,(ab+bc+ca=0)     

 

 

 

Required mean =a2+b2+c23=9M23=3M2 .

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Q:

A student was asked to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What should be the number in place of x ?

A) 6 B) 7
C) 8 D) 9
 
Answer & Explanation Answer: B) 7

Explanation:

Clearly, we have (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x) / 12 = 12.

or  137 + x = 144 or x = 144 - 137 = 7.

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Q:

The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what ia the pice of each of these two books ?

A) 16,12 B) 10,16
C) 23,9 D) 8,7
 
Answer & Explanation Answer: B) 10,16

Explanation:

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]

 

                                          = Rs. (120 - 94) = Rs. 26.

 

let the price of one book be Rs. x

 

Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x

 

So,  x+(8/5)x =26 <=> x =10

 

The prices of the two books are Rs. 10 and Rs. 16

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Q:

The average price of three items of furniture is Rs. 15000. If their prices are in the ratio 3:5:7, the price of the cheapest item is :

A) 6000 B) 7000
C) 8888 D) 9000
 
Answer & Explanation Answer: D) 9000

Explanation:

Let their prices be 3x,  5x and 7x.

Then, 3x + 5x + 7x = (15000 * 3) or x = 3000.

Cost of cheapest item = 3x = Rs. 9000.

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Q:

What are set up time & hold time constraints? What do they signify? Which one is critical for estimating maximum clock frequency of a circuit?

Answer

Suppose your flip-flop is positive edgetriggered. time for which data should be stable prior to positive edge clock is called setup is called setup time constraint.


Time for which data should be stable after the positive edge of clock is called as hold time constraint.


If any of these constraints are violate d then flip-flop will enter in meta stable state, in which we cannot determine the output of flip-flop.


there are two equation:


1. Tcq + Tcomb > Tskew + Thold


2. Tcq + Tcomb > Tskew + T - Tsetup


Tcq is time delay when data enters the flip flop and data comes at output of flip flop.


Tcomb is the logic delay between two flip flop.


Tskew is the delay of clock to flip flop: suppose there are two flip flop, if clock reaches first to source flip flop and then after some delay to destination flip flop, it is positive skew and if vice versa then negative  skew. 


so if you take 2 eq you will see that setup time is the determining factor of clock's time period.

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Subject: Hardware