The Bhindawas Bird Sanctuary (BBS) is located in Jhajjar district, Haryana. It is home to many birds such as Blue Peafowl, Gray Francolin, Black Francolin, Shikra, Black Kite, Greater Coucal, White-throated Kingfisher, Coppersmith Barbet and Indian Roller. It is in news because the sanctuary will soon be developed as a beautiful tourist resort and the additional facilities to be provided to the tourists coming to this place would include arrangements for camping for night stay, beautification of the lake, and opening of dispensary for birds and the wild life.

Orkut’s creator Buyukkokten has launched a new social network called Hello, which is available on mobile only. The Hello.com app is available on Android and iOS in the following countries: US, Canada, Britain, France, Australia, Brazil, Ireland. Germany, Mexico and India are next on the list and the app should be available this month.

A semi-mechanised car park, the first of its kind in Jammu and Kashmir, was inaugurated by Chief Minister Mehbooba Mufti who hoped the facility would ease traffic congestion in and around Lal Chowk. The multi-level car park, located near the old KMD bus stand on Maulana Azad Road, has been set up at a cost of Rs 27.15 crore and has a capacity to hold 288 vehicles.

Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs

Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.

We know that I = PTR/100
=> P = 20250/4.5 = 4500
Now, new Interest at 5% = 4500x1x5/100 = 225
Now the additional amount = 225 - 202.5 = Rs. 22.5

Let the number be 'N'
Given N + 30N/100 = 390
=> 130N/100 = 390
=> N = 390 x 10/13
=> N = 300.

I = PTR/100
I = 25 x 4 x 0.03/100
I = 0.03 x 100 = 300 Ps = Rs. 3

Let the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy

=>5(300/x) - 10x - 50 = 0 => -150+x2+5x

multiplying both sides by -1/10x

=> x2+15x-10x-150=0

=> x(x + 15) - 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.