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Q:

If the positions of the first and the fifth digits of the number 14278359 are interchanged, similarly the positions of the second and the sixth digits are interchanged and so on, then which of the following will be the second digit from the right end after the rearrangement ?

A) 5	B) 2
C) 7	D) 4

Answer & Explanation Answer: B) 2

Explanation:

Given number is 14278359
As given 1st and 5th digits, 2nd & 6th, 3rd & 7th and 4th & 8th digits are to to be interchanged.
Therfore, the rearranged number is 83591427
Then, the second digit from the right end is 2.

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Filed Under: Arithmetical Reasoning
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Q:

Choose what replaces '?' in the following figure ?

creative111486456294.jpg image

A) Q	B) O
C) M	D) N

Answer & Explanation Answer: D) N

Explanation:

The alphabetical value of the letters in the left hand column follows through the sequence of Prime Numbers, with the letters in the right hand column representing the corresponding reverse alphabetical values. So,

M = Reverse of M = N.

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Filed Under: Missing letters puzzles
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Q:

On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ?

A) Wednesday	B) Tuesday
C) Friday	D) Thursday

Answer & Explanation Answer: A) Wednesday

Explanation:

The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.

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Filed Under: Calendar
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Q:

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ?

A) Rs.14,000	B) Rs.12,000
C) Rs. 12,800	D) Rs. 15,000

Answer & Explanation Answer: B) Rs.12,000

Explanation:

We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
= $\frac{P}{{(1 + \frac{R}{100})}^{n}}$ = $\frac{8748}{{(1 - \frac{10}{100})}^{3}}$
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.

Therefore, the purchase price of the machine was Rs. 12,000.

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Filed Under: Percentage
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Q:

In measuring the sides of a rectangle, one side is taken 20% in excess and the other 10% in deficit. Find the error per cent in area calculated from the measurement ?

A) 8% excess	B) 9% deficit
C) 12% excess	D) 11% deficit

Answer & Explanation Answer: A) 8% excess

Explanation:

Since Area of Rectangle = side1 x side2
Therefore, error% in area
= $x + y + \frac{x y}{100}$ %
= [20 - 10 + ( -10 x 20)/100]% or 8%
i.e. 8% excess.

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Filed Under: Percentage
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Q:

A number is increased by 20% and then decreased by 20%, the final value of the number is ?

A) increase by 2%	B) decrease by 3%
C) decrease by 4%	D) increase by 5%

Answer & Explanation Answer: C) decrease by 4%

Explanation:

Here, x = 20 and y = - 20
Therefore, the net % change in value
= $x + y + \frac{x y}{100}$ %
= $20 + (- 20) + \frac{20 \times - 20}{100}$ % or - 4%

Since the sign is negative, there is a decrease in value by 4%.

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Filed Under: Percentage
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Q:

The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ?

A) 16%	B) 20%
C) 84%	D) 72%

Answer & Explanation Answer: B) 20%

Explanation:

Reduction in consumption
= $\frac{P}{100 + P}$ X 100%
= $\frac{25}{100 + 25}$ X 100%
= 20%

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Filed Under: Percentage
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Q:

Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ?

A) 92.8%	B) 84.23%
C) 87.14%	D) 94.1%

Answer & Explanation Answer: A) 92.8%

Explanation:

Here, x = 40 and y = 30;
Therefore second number
= [[ $\frac{100 + y}{100 + x}$ ] x 100 ]% of first number
= [[ $\frac{100 + y}{100 + x}$ ] x 100 ]% of first number
Second number = 92.8% of the first number.

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Filed Under: Percentage
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