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Q:

Who among the following presented union budget maximum number of times ?

A) P. Chidambaram	B) Pranab Mukerji
C) R.V. Shanmukham chetty	D) Morarji Desai

Answer & Explanation Answer: D) Morarji Desai

Explanation:

Morarji Desai, the former finance , prime minister had presented the Union budget for 10 times.

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Filed Under: Indian Economy
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Q:

The average of a non-zero number and its square is 11 times the number. The number is ?

A) 22	B) 21
C) 11	D) 17

Answer & Explanation Answer: A) 22

Explanation:

Let the number be 'x'.

$\frac{x + x^{2}}{2}$ = 11x
$x^{2}$ = 22x
=> x = 22.

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Q:

Total number of students in 3 classes of a school is 333 . The number of students in class 1 and 2 are in 3:5 ratio and 2 and 3 class are 7:11 ratio . What is the strength of class that has highest number of students ?

A) 125	B) 155
C) 135	D) 165

Answer & Explanation Answer: D) 165

Explanation:

Ratio C1:C2 = 3:5 and C2:C3 = 7:11
So C1:C2:C3 = 21 : 35 : 55
Let the strength of three classes are 21x, 35x and 55x respectively, then
Given that 21x + 35x + 55x = 333
=> 111x = 333 or x=3
So strength of the class with highest number of students =55x = 55x3 = 165.

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Filed Under: Ratios and Proportions
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Q:

A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ?

A) 1:3	B) 2:1
C) 3:2	D) 2:3

Answer & Explanation Answer: C) 3:2

Explanation:

Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7

We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7

Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9

Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.

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Filed Under: Ratios and Proportions
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Q:

How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ?

A) 521	B) 720
C) 420	D) 225

Answer & Explanation Answer: B) 720

Explanation:

Let last digit is 2
when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.
so for last digit = 2, total numbers=240

Similarly for 4 and 6
When last digit = 4, total no. of ways =240
and last digit = 6, total no. of ways =240
so total of 720 even numbers are possible.

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Filed Under: Permutations and Combinations
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Q:

A number of cats got together and decided to kill between them 999919 rats. Every cat killed an equal number of rats. Each cat killed more rats than there were cats. How many rats do you think that each cat killed ?

A) 1009	B) 991
C) 2000	D) 1000

Answer & Explanation Answer: A) 1009

Explanation:

Given total number of rats = 999919

999919 = 1000000 - 81 = $(1000^{2} - 9^{2})$ = (1000+9)(1000-9) = 1009 x 991.
Since there were more rats than there were cats, 991 cats killed 1009 rats each.

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Filed Under: Math Puzzles
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Q:

If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?

A) 6	B) 8
C) 4	D) 9

Answer & Explanation Answer: C) 4

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

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Filed Under: HCF and LCM
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Q:

Find the number of factors of 9321 ?

A) 4	B) 5
C) 7	D) 8

Answer & Explanation Answer: D) 8

Explanation:

9321 = 3 x 13 x 239 = 31 x 13 1 x 239 1 ; add one to all the powers ie.,

(1+1) x (1+1) x (1+1)= 8 ;

we get eight factors.

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Filed Under: Numbers
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