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Q:

What is the probability of getting a sum 9 from two throws of a dice?

A) 1/2 B) 3/4
C) 1/9 D) 2/9
 
Answer & Explanation Answer: C) 1/9

Explanation:

In two throws of a die, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) =n(E)/n(S)=4/36=1/9.

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Filed Under: Probability

Q:

A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.600 more. What was the Sum?

A) Rs.1200 B) Rs.1300
C) Rs.1400 D) Rs.1500
 
Answer & Explanation Answer: A) Rs.1200

Explanation:

At 5% more rate, the increase in S.I for 10 years = Rs.600  (given)

So, at 5% more rate, the increase in SI for 1 year = 600/10 = Rs.60/-

i.e. Rs.60 is 5% of the invested sum

So, 1% of the invested sum = 60/5

Therefore, the invested sum = 60 × 100/5 = Rs.1200

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

A) 10/21 B) 11/21
C) 1/2 D) 2/7
 
Answer & Explanation Answer: A) 10/21

Explanation:

Total number of balls = (2 + 3 + 2) = 7.

 

Let S be the sample space.

 

Then, n(S) = Number of ways of drawing 2 balls out of 7 =7C2 = 21

 

Let E = Event of drawing 2 balls, none of which is blue.

 

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls =5C2 = 10

 

Therefore, P(E) = n(E)/n(S) = 10/ 21.

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Q:

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

A) 1/3 B) 3/5
C) 8/21 D) 7/21
 
Answer & Explanation Answer: A) 1/3

Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green 

            = event that the ball drawn is blue.

n(E) = 7.

P(E) = n(E)/n(S) = 7/21 = 1/3.

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Q:

A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interst. The rate per annum 

A) 5% B) 5.5%
C) 6% D) 6.5%
 
Answer & Explanation Answer: B) 5.5%

Explanation:

sum = x. amount =7x/6.

S.I. =(7x/6 – x) = x/6 ; time = 3 years

Rate =[ (100 * x) / (x * 6 * 3)]% = 5.5%

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Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

A) 1/2 B) 3/5
C) 9/20 D) 8/15
 
Answer & Explanation Answer: C) 9/20

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E)/n(S) = 9/20.

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Filed Under: Probability

Q:

If a sum of money at simple interest doubles in 6 years, it will become  4 times in

A) 15years B) 16years
C) 17years D) 18years
 
Answer & Explanation Answer: D) 18years

Explanation:

 

 

 

 

 

 

let sum =x . s.i.=x

 

 

 

rate =(100*x)/(x*6)=50/3%

 

 

 

now ,sum =x, s.i= 3x, rate =50/3%

 

 

 

time =(100*3x)/(x*50/3) = 18 years

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Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only
 
Answer & Explanation Answer: D) Either II or III only

Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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