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Q:

Insert the missing number.

16, 33, 65, 131, 261, (....)

A) 523	B) 521
C) 613	D) 721

Answer & Explanation Answer: A) 523

Explanation:

Each number is twice the preceding one with 1 added or subtracted alternatively.

So, the next number is (2 x 261 + 1) = 523.

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Filed Under: Odd Man Out

Q:

Find out the wrong number in the given sequence of numbers.

36, 54, 18, 27, 9, 18.5, 4.5

A) 4.5	B) 18.5
C) 54	D) 18

Answer & Explanation Answer: B) 18.5

Explanation:

The terms are alternatively multiplied by 1.5 and divided by 3. However, 18.5 does not satisfy it.

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Filed Under: Odd Man Out

Q:

Find out the wrong number in the given sequence of numbers.

6, 13, 18, 25, 30, 37, 40

A) 25	B) 30
C) 37	D) 40

Answer & Explanation Answer: D) 40

Explanation:

The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5.

So, 40 is wrong.

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Filed Under: Odd Man Out

Q:

Find out the wrong number in the given sequence of numbers.

582, 605, 588, 611, 634, 617, 600

A) 634	B) 611
C) 605	D) 600

Answer & Explanation Answer: A) 634

Explanation:

Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.

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Q:

Find out the wrong number in the given sequence of numbers.

5, 16, 6, 16, 7, 16, 9

A) 9	B) 7
C) 6	D) None of these

Answer & Explanation Answer: A) 9

Explanation:

Terms at odd places are 5, 6, 7, 8 etc. and each term at even place is 16.

So, 9 is wrong.

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Q:

A man buys oranges at Rs 5 a dozen and an equal number at Rs 4 a dozen. He sells them at Rs 5.50 a dozen and makes a profit of Rs 50. How many oranges does he buy?

A) 30 dozens	B) 40 dozens
C) 50 dozens	D) 60 dozens

Answer & Explanation Answer: C) 50 dozens

Explanation:

Cost Price of 2 dozen oranges Rs. (5 + 4) = Rs. 9.
Sell price of 2 dozen oranges = Rs. 11.
If profit is Rs 2, oranges bought = 2 dozen.
If profit is Rs. 50, oranges bought = (2/2) * 50 dozens = 50 dozens.

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Filed Under: Profit and Loss

Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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Subject: Table Charts Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

Q:

The following chart represents the number of students who passed the CAT exam or the XAT exam or the CET exam or None of these exams. (Assume that there are no students who passed more than one exam.)

Number of students who qualified CAT/XAT/CET Exams

1. Which year showed the best result in MBA entrance exams (in terms of percentage of students who cleared) ?

1. 2000 2. 2001 3. 2002 4. Cannot be determined

2. What was the percentage of students who succeeded in at least one of three exams in 2000 ?

1. 82.4% 2. 82.8% 3. 82.35% 4. 83.3%

3. What is the percentage increase in the number of students in 2002 over 2000 ?

1. 30% 2. 17.64% 3. 117.6% 4. 85%

4. What is the percentage of students who cleared CAT in 2000 ?

1. 19.56% 2. 12.65% 3. 14.28% 4. 11.76%

Answer

1. ANSWER : 2

Explanation - Compare the respective pass percentage for three years : 2000, 2001 and 2002

= (140 x 100)/170 < (150 x 100)/180 and (150 x 100)/180 > (160 x 100)/200

= 82.35% < 83.33% and 83.33% > 80%

2. ANSWER : 3

Explanation - Total percentage of students who succeeded in at least one of three exams in 2000 = (140 x 100)/170= 82.35 %

3. ANSWER : 2

Explanation - Total percentage increase in the number of students in 2002 over 2000 is = (30 x 100)/170 =17.64 %

4. ANSWER : 4

Explanation - Total percentage of students who cleared CAT in 2000 =(20 x 100)/170 = 11.76 %

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