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Q:

The ratio of investments of two partners is 11:12 and the ratio of their profits is 2 : 3. If A invested the money for 8 months , find for how much time B invested his money.

Answer

Suppose A invested Rs.11 for 8 months and B invested Rs. 12 for x months.

$\inline \therefore$ Ratio of investments of A and B

= (11 x 8) : (12 x x)

= 88 : 12x

$\inline \therefore$ $\inline \frac{88}{12x}=\frac{2}{3}\Rightarrow x=11$

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Subject: Partnership

Q:

A and B enter into partnership. A supplies whole of the capital amounting to Rs. 45000 with the condition that the profits to be equally divided and that B pays A interest on half of the capital at 10% per annum, but receives Rs. 120 per month for carrying on the concern.Find their total yearly profit when B's income is one half of A's income.

Answer

Let the total profit be Rs. x

Amount paid to B as salary = (120 x 12)

= Rs.1440

Share of each = $\inline (\frac{x-1440}{2})$

Interest paid by B = $\inline \frac{22500\times 10}{100}=Rs.2250$

Total money received by A = $\inline \frac{x-1440}{2}+2250$

= Rs. $\inline (\frac{x+3060}{2})$

Total money received by B

$\inline [(\frac{x-1440}{2})+1440-2250]= (\frac{x-3060}{2})$

$\inline \Rightarrow \frac{1}{2}-(\frac{x+3060}{2})-(\frac{x-3060}{2})$

$\inline \Rightarrow x=9180$

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Subject: Partnership

Q:

Three graziers A,B and C rent a piece of pasture for a month. A puts in 27 cattle for 19 days, B 21 for 17 days and C 24 for 23 days. If at the end of the month the rent amount to Rs.237, how much ought to be paid by each.

Answer

A's cattle = 27 x 19 = 513

B's cattle = 21 x 17 = 357

C's cattle = 24 x 23 = 552

Ratio of cattle = 513 : 357 : 552

= 171 : 119 : 184

payment to be made by A = $\inline 237\times \frac{171}{474}$

= Rs.85.50

payment to be made by B = $\inline 237\times \frac{119}{474}$

= Rs.59.50

payment to be made by C = $\inline 237\times \frac{184}{474}$

= Rs.92

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Subject: Partnership

Q:

The tax on an article decreases by 10% and its consumption increases by 10%. Find the effect percent on its revenue?

Answer

$- 10 + 10 - \frac{10 * 10}{100}$ % = -1%

$\inline \therefore$ Decrease in revenue = 1%

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Subject: Percentage Exam Prep: Bank Exams

Q:

In an election, there were two candidates only. The candidate who got 62% of the total votes polled and was elected by a majority of 192 votes. The total number of votes polled was?

Answer

Suppose total votes polled is x

$\inline \Rightarrow$ $\inline \frac{62x}{100}=\frac{38x}{100}+192$

$\inline \Rightarrow \frac{62x}{100}-\frac{38x}{100}=192$

$\inline \Rightarrow \frac{24x}{100}=192\Rightarrow x=800$

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Subject: Percentage

Q:

Two numbers are 20% and 30% less than the third number . How much percent is the second number less than first?

Answer

Let the third number be 100.

Then, the first number = 100 - 20 = 80 and second number = 100 - 30 = 70.

Difference between the first and second number = 80-70 = 10

$\inline \therefore$ Required percentage = $\frac{10}{80} x 100$ % = 100/8 = 12.5%

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Subject: Percentage Exam Prep: Bank Exams

Q:

Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respectively . If these pipes are turned on alternately for 1 minute each how long will it take to the cistern to fill?

Answer

As the pipes are operating alternatively, thus their 2 minutes job is = $\frac{1}{4} + \frac{1}{6} = \frac{5}{12}$

In the next 2 minutes the pipes can fill another $\frac{5}{12}$ part of cistern.

Therefore, In 4 minutes the two pipes which are operating alternatively will fill $\frac{5}{12} + \frac{5}{12} = \frac{5}{6}$ Remaining part = $1 - \frac{5}{6} = \frac{1}{6}$

Pipe A can fill $\frac{1}{4}$ of the cistern in 1 minute

Pipe A can fill $\frac{1}{6}$ of the cistern in = $\frac{2}{3}$ min

Therefore, Total time taken to fill the Cistern

4 + $\frac{2}{3}$ minutes.

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Subject: Time and Work Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

A contractor undertakes to complete a work in 130 days. He employs 150 men for 25 days and they complete 1/4 of the work . He then reduces the number of men to 100, who work for 60 days, after which there are 10 days holidays.How many men must be employed for the remaining period to finish the work?

Answer

150 men in 25 days do = $\frac{1}{4}$ work

Let 1 man in 1 day does = x work

Total work done by 150 men in 25 days = 150x * 25 = $\frac{1}{4}$ work => x = $\frac{1}{15000}$

Therefore, 100 men in 60 days do = 100 * 60x = 6000x work = 6/15 = 2/5

Total work done = $\frac{1}{4} + \frac{2}{5} = \frac{13}{20}$

Therefore, Remaining work = 1 - $\frac{13}{20}$ = $\frac{7}{20}$

Remaining time = 130 - (25+60+10) = 35 days

Therefore, work is done in 25 days by 150 men.

Therefore, Work is done in 35 days by 150 men.

Hence, he should employ 50 more men.

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Subject: Time and Work Exam Prep: Bank Exams , AIEEE
Job Role: Bank PO

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