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Q:

What was the day of the week on 17th June, 1998?

A) Wednesday	B) Saturday
C) Friday	D) Tuesday

Answer & Explanation Answer: A) Wednesday

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday

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Q:

What was the day on 15th august 1947 ?

A) Friday	B) Saturday
C) Sunday	D) Thursday

Answer & Explanation Answer: A) Friday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

15th_August_1947_day1534219857.jpg image

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Hence, as the number of odd days = 5 , given day is Friday.

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Q:

The calendar of the year 2024 can be used again in the year?

A) 2030	B) 2052
C) 2048	D) 2036

Answer & Explanation Answer: B) 2052

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2: Add +6 to the Given Year.

Solution :

Given Year is 2024, Which is a leap year.

So, Add +28 to the given year (i.e 2024 + 28) = 2052

Therfore, The calendar of the year 2024 can be used again in the year 2052.

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Q:

Which century year is a leap year?

A) 1900	B) 1700
C) 1600	D) 1100

Answer & Explanation Answer: C) 1600

Explanation:

NOTE: For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year.

So, 1600

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Q:

The calendar of the year 2006 was used before in the year?

A) 1990	B) 1995
C) 2002	D) 2000

Answer & Explanation Answer: B) 1995

Explanation:

Given year 2006, when divided by 4 leaves a remainder of 2.

NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.

So, 2006 - 11 = 1995

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Q:

Which calendar was used again in the year 1856?

A) 1828	B) 1850
C) 1830	D) 1852

Answer & Explanation Answer: A) 1828

Explanation:

Given year 1856, when divided by 4 leaves a remainder of 0.

NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.

So, 1856 - 28 = 1828

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Q:

The calendar of the year 1897 can be used again in the year?

A) 1908	B) 1901
C) 1903	D) 1926

Answer & Explanation Answer: C) 1903

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2: Add +6 to the Given Year.

Solution :

Given Year is 1897, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 1897 + 11) = 1908, Which is a leap year.

Step 2 : Add +6 to the given year (i.e 1897 + 6) = 1903

Therfore, The calendar of the year 1897 can be used again in the year 1903

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Q:

If log 2 = 0.3010 and log 3 = 0.4771, the values of log₅ 512 is

A) 2.875	B) 3.875
C) 4.875	D) 5.875

Answer & Explanation Answer: B) 3.875

Explanation:

ANS: log₅512 = log512/log5 = $\frac{\log 2^{9}}{\log (10 / 2)}$ = $\frac{9 \log 2}{\log 10 - \log 2}$ = $\frac{9 * 0.3010}{1 - 0.3010}$ =2.709/0.699 =2709/699 =3.876

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Filed Under: Logarithms
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