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Q:

Find the area of the rectangle or square with the given dimensions s=10 feet

A) 500	B) 100
C) 200	D) 300

Answer & Explanation Answer: B) 100

Explanation:

$A = S^{2}$

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Q:

Find the area of the rectangle or square with the given dimensions L = 5 inches, W= 3 inches?

A) 13	B) 14
C) 15	D) 16

Answer & Explanation Answer: C) 15

Explanation:

We know that,

Area of rectangle A = L x W = 5 x 3 = 15 sq.inches.

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Q:

Find the perimeter of the rectangle or square with the given dimensions s = 3 cm

A) 12	B) 13
C) 14	D) 15

Answer & Explanation Answer: A) 12

Explanation:

P=4s

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Q:

Find the perimeter of the rectangle or square with the given dimensions l = 5 feet, w = 2 feet?

A) 11ft	B) 13ft
C) 14ft	D) 15ft

Answer & Explanation Answer: C) 14ft

Explanation:

We know that,

Perimeter of rectangle = 2(L+W) = 2(5 + 2) = 2 (7) = 14 fts.

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Q:

The area of a square is 49 mm. What is the length of each side?

A) 5mm	B) 6mm
C) 7mm	D) 8mm

Answer & Explanation Answer: C) 7mm

Explanation:

$A = S^{2}$

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Q:

The perimeter of a square is 40 meters. Find the length of one side of the square

A) 10m	B) 20m
C) 30m	D) 40m

Answer & Explanation Answer: A) 10m

Explanation:

P = 4 x s

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Q:

The length of a rectangular plot is 20 meters more than its breadth. If the cost of fencing the plot @ 26.50 per meter is Rs. 5300. What is the length of the plot in meter?

A) 40m	B) 50m
C) 60m	D) 10m

Answer & Explanation Answer: C) 60m

Explanation:

let breadth = x then length = x+20

perimeter = 5300/26.50 = 200m

2(x+20+x) =200 => 4x+40 =200

x = 40 and length = 40+20 = 60m

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Q:

A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?

A) 65m	B) 45m
C) 55m	D) 56m

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