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Q:

A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?

A) 10%	B) 20%
C) 30%	D) 40%

Answer & Explanation Answer: C) 30%

Explanation:

let the side of the square be x meters
length of two sides = 2x meters
diagonal = $\sqrt{2 x}$ = 1.414x m

saving on 2x meters = .59x m

saving % = $\frac{0.59 x}{2 x} * 100$ %

= 30% (approx)

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Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800	B) 43800
C) 83800	D) 73800

Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Q:

A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

A) rs.58	B) rs.158
C) rs.258	D) rs.358

Answer & Explanation Answer: C) rs.258

Explanation:

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m

cost of graveling = 344 x (75/100) = Rs. 258

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Q:

A took 15 seconds to cross a rectangular field diagonally walking at the rate of 52 m/min and B took the same time to cross the same field along its sides walking at the rate of 68m/min. The area of the field is?

A) 50	B) 60
C) 70	D) 80

Answer & Explanation Answer: B) 60

Explanation:

length of the diagonal = 52 x (15/60) =13m

sum of length and breadth = 68 x (15/60) = 17m

$(\sqrt{l^{2} + b^{2}}) = 13 o r l + b = 17$

area =lb = 1/2[(2lb)] = 1/2[(l+b)² - (l²+b²)] = 1/2[17² -169]

=1/2 x 120 = 60 sq.m

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Q:

A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper?

A) 140	B) 150
C) 160	D) 170

Answer & Explanation Answer: A) 140

Explanation:

when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cm

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Q:

Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is

A) 12	B) 32
C) 42	D) 52

Answer & Explanation Answer: C) 42

Explanation:

required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm

= 196 - 154 = 42 sq.cm.

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Q:

A particle which is four times in mass and two times in charge that of proton is

A) helium atom	B) an alpha particle
C) deuteron	D) tritium

Answer & Explanation Answer: B) an alpha particle

Explanation:

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Q:

Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is

A) 1.967	B) 1.867
C) 1.767	D) 1.567

Answer & Explanation Answer: A) 1.967

Explanation:

required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with Ã = 60 degrees and r = 3.5cm)
$(\frac{\sqrt{3}}{4} * 7 * 7) - (3 * \frac{22}{7} * 3.5 * 3.5 * \frac{60}{360})$ sq cm

= $(\frac{\sqrt{3}}{4} * 49) - (11 * 0.5 * 3.5)$ sq cm

= 1.967 sq cm

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