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Q:

Five plays P, Q, R, S and T were organised in a week from Monday to Saturday with one play each day and no play was organised on one of these days. Play S was organised before Thursday but after Monday. Play T was organised on Saturday. Play R was not organised on the first day. Play Q was organised on the next day on which play R was organised. Play P was organised on Tuesday.

1) On which day was play Q organised ?

2) On which day was no play organised ?

3) Which play was organised on Thursday ?

Answer

Day Play

Monday No play
Tuesday P
Wednesday S
Thursday R
Friday Q
Saturday T

Answers :

From the above table :

1) On Friday play Q was organised.

2) On Monday Noplay was organised.

3) On Thursday Play R was organised.

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Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8	B) 25.2 and 50.4
C) 31.4208 and 62.8416	D) 33.12 and 66.24

Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
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Q:

There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ?

A) 1000	B) 625
C) 525	D) 125

Answer & Explanation Answer: D) 125

Explanation:

Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5

So total methods = 5 x 5 x 5 = 125.

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Filed Under: Permutations and Combinations
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Q:

There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ?

A) 42 & 24	B) 38 & 26
C) 36 & 24	D) 44 & 28

Answer & Explanation Answer: D) 44 & 28

Explanation:

Let
x = peacocks
y = deers

2x + 4y = 200
x + y = 72
y = 72 - x
2x + 288 - 4x = 200
x = 44 peacocks
y = 28 deers

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Filed Under: Numbers
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Q:

A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ?

A) 39 days	B) 37 days
C) 35 days	D) 33 days

Answer & Explanation Answer: C) 35 days

Explanation:

Distance d = 1200km
let S be the speed

he walks 15 hours a day(i.e 24 - 9)
so totally he walks for 70 x 15 = 1050hrs.

S = 1200/1050 => 120/105 = 24/21 => 8/7kmph

given 1 1/2 of previous speed
so 3/2 * 8/7= 24/14 = 12/7

New speed = 12/7kmph

Now he rests 10 hrs a day that means he walks 14 hrs a day.

time = 840 x 7 /12 => 490 hrs
=> 490/14 = 35 days

So he will take 35 days to cover 840 km.

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Filed Under: Time and Distance
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Q:

A class consists of both boys and girls along with a teacher. After a class, the teacher drinks 9 litres of water, a boy drinks 7 litres of water and a girl drinks 4 litres of water. If after a class 42 litres of water was consumed, find the number of girls in the class ?

A) 8	B) 6
C) 5	D) 3

Answer & Explanation Answer: D) 3

Explanation:

Given teacher drinks 9 ltr
Let number of boys be 'A'.
Let number of girls be 'B'.
Boy drinks 7 ltr and girl drinks 4 ltr
After class total water consumed = 42 ltr
Then,
9 + 7A + 4B = 42
=> 7A + 4B = 33
By trial and error method,
The only integers which satisfy the equation is A = 3 and B = 3
Therefore, number of girls in the class = 3.

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Filed Under: Simplification
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Q:

Fill in the blanks with the appropriate words.

Countries which _________ still undergoing the economic processes
_________ known as developing countries.

A) are, are	B) are, is
C) is, are	D) were, are

Answer & Explanation Answer: A) are, are

Explanation:

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Filed Under: Analogy
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Q:

If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ?

A) 51/1221	B) 42/221
C) 1/221	D) 52/1245

Answer & Explanation Answer: C) 1/221

Explanation:

Total Combination of getting a card from 52 cards = ${}^{52}C_{1}$

Because there is no replacement, so number of cards after getting first card= 51

Now, Combination of getting an another card= ${}^{51}C_{1}$

Total combination of getting 2 cards from 52 cards without replacement= ( ${}^{52}C_{1} \times {}^{51}C_{1}$ )

There are total 4 Ace in stack. Combination of getting 1 Ace is = ${}^{4}C_{1}$

Because there is no replacement, So number of cards after getting first Ace = 3

Combination of getting an another Ace = ${}^{3}C_{1}$

Total Combination of getting 2 Ace without replacement= ${}^{4}C_{1} \times {}^{3}C_{1}$

Now,Probability of getting 2 cards which are Ace = $\frac{{}^{4}C_{1} \times {}^{3}C_{1}}{{}^{52}C_{1} \times {}^{51}C_{1}}$ = 1/221.

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Filed Under: Permutations and Combinations
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