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Q:

Observe the dots on a dice (one to six dots) in the following figures. How many dots are contained on the face opposite to that containing four dots?

A) 2	B) 3
C) 6	D) Cannot be determined

Answer & Explanation Answer: A) 2

Explanation:

We shall assume the dice in fig. (ii) to be rotated so that the 5 dots appear at the same position as in fig. (i) i.e. on RHS face (i.e. on face II as per activity 1) and 1 dot appears at the same position as in fig; (i) i.e. on Front face (i.e. on face I). Then, from the, two figures, 2 dots appear on the top face (i.e. on face V) and 4 dots appear on the Bottom face (i.e. on face VI).

Since, these two faces are opposite to each other, therefore, two dots are contained on the face opposite to that containing four dots.

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Filed Under: Cubes and Dice

Q:

A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:

A) No profit, no loss	B) 5%
C) 8%	D) 10%

Answer & Explanation Answer: B) 5%

Explanation:

C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.

S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.

Gain =(80/1600*100) % = 5%

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Filed Under: Profit and Loss

Q:

The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?

A) Rs. 2000	B) Rs. 2200
C) Rs. 2400	D) Data inadequate

Answer & Explanation Answer: A) Rs. 2000

Explanation:

Let C.P. be Rs. x.

Then,= > $\frac{1920 - x}{x} * 100 = \frac{x - 1280}{x} * 100$

=> 1920 - x = x - 1280

=> 2x = 3200

=> x = 1600

Required S.P. = 125% of Rs. 1600 =Rs(125/100*1600) = Rs2000

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Filed Under: Profit and Loss

Q:

The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

A) 15	B) 16
C) 18	D) 25

Answer & Explanation Answer: B) 16

Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

$(\frac{20 - x}{x} * 100 = 25)$

=> 2000 - 100x = 25x

=> 125x=2000

=> x=16

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Filed Under: Profit and Loss

Q:

Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

A) 10 min. 20 sec.	B) 11 min. 45 sec.
C) 12 min. 30 sec.	D) 14 min. 40 sec.

Answer & Explanation Answer: D) 14 min. 40 sec.

Explanation:

Part filled in 4 minutes =4(1/15+1/20) = 7/15

Remaining part =(1-7/15) = 8/15

Part filled by B in 1 minute =1/20 : 8/15 :: 1:x

x = (8/15*1*20) = $10 \frac{2}{3} m i n = 10 m i n 40 s e c$

The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec

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Filed Under: Pipes and Cistern

Q:

Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:

A) 60 gallons	B) 100 gallons
C) 120 gallons	D) 180 gallons

Answer & Explanation Answer: C) 120 gallons

Explanation:

Work done by the waste pipe in 1 minute = $\frac{1}{15} - (\frac{1}{20} + \frac{1}{24}) = \frac{1}{15} - \frac{11}{120} = - \frac{1}{40}$ [-ve sign means emptying]

Volume of $\frac{1}{40}$ part = 3 gallons

Volume of whole = (3 x 40) gallons = 120 gallons.

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

A pump can fill a tank with water in 2 hours. Because of a leak, it took $2 \frac{1}{3}$ hours to fill the tank. The leak can drain all the water of the tank in:

A) 7 hours	B) 8 hours
C) 12 hours	D) 14 hours

Answer & Explanation Answer: D) 14 hours

Explanation:

If the total area of pump=1 part

The pumop take 2 hrs to fill 1 part

The pumop take1 hour to fill 1/2 portion

Due to lickage

The pumop take 7/3 hrs to fill 1 part

The pumop take1 hour to fill 3/7 portion

Now the difference of area = (1/2-3/7)=1/14

This 1/14 part of water drains in 1 hour

Total area=1 part of water drains in (1x14/1)hours= 14 hours

So the leak can drain all the water of the tank in 14 hours.

Leak will empty the tank in 14 hrs

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Filed Under: Pipes and Cistern
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?

A) 3 hrs 15 min	B) 3 hrs 45 min
C) 4 hrs 15 min	D) 4 hrs 1

Answer & Explanation Answer: B) 3 hrs 45 min

Explanation:

Time taken by one tap to fill half of the tank = 3 hrs.

Part filled by the four taps in 1 hour =4*1/6 =2/3

Remaining part = $(1 - \frac{1}{2}) = \frac{1}{2}$

$\frac{2}{3} : \frac{1}{2} : : 1 : x$

=> x = $(\frac{1}{2} * 1 * \frac{3}{2}) = \frac{3}{4}$

So, total time taken = 3 hrs. 45 mins.

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Filed Under: Pipes and Cistern

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