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Q:

A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

A) 315	B) 385
C) 415	D) 485

Answer & Explanation Answer: A) 315

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, $[x - (700 - x)] = \frac{1}{5} [\frac{x + (700 - x)}{2}]$

$\Rightarrow 2 x - 700 = 70$

$\Rightarrow x = 385$

So, the two parts are 385 and 315.

Hence, Area of the smaller = 315 hectares

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Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?

A) 44ft	B) 88ft
C) 22ft	D) 11ft

Answer & Explanation Answer: B) 88ft

Explanation:

Given that length and area, so we can find the breadth.

Length x Breadth = Area

=> 20 x Breadth = 680

=> Breadth = 34 feet

Area to be fenced = 2B + L = 2 (34) + 20 = 88 feet

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Q:

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is

A) 200m	B) 300m
C) 400m	D) 100m

Answer & Explanation Answer: A) 200m

Explanation:

Let the triangle and parallelogram have common base b,

let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then

Area of triangle = $\frac{1}{2} \times b \times h 1$

Area of rectangle = b*h2

As per Given,

$\frac{1}{2} * b * h 1 = b * h 2$

$\frac{1}{2} * b * h 1 = b * 100$

h1=200

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Q:

A rectangular parking space is marked out by painting three of its sides.If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet?

A) 126sq.ft	B) 120sq.ft
C) 130sq.ft	D) 135sq.ft

Answer & Explanation Answer: A) 126sq.ft

Explanation:

Let l = 9 ft.

Then l + 2b = 37

=> 2b = 37 – l = 37 – 9 = 28

b = 28/2 = 14 ft.

Area = lb = 9 × 14 = 126 sq. ft.

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Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20	B) 200
C) 300	D) 400

Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40] * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters.

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Q:

The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?

A) 47500	B) 37500
C) 57500	D) 77500

Answer & Explanation Answer: B) 37500

Explanation:

Let length = x meters, then breadth = 0.6x

Given that perimeter = 800 meters

=> 2[ x + 0.6x] = 800

=> x = 250 m

Length = 250m and breadth = 0.6 x 250 = 150m

Area = 250 x 150 = 37500 sq.m

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Q:

The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 sq.m. The length of the hall is

A) 20	B) 25
C) 30	D) 35

Answer & Explanation Answer: C) 30

Explanation:

Let breadth = x m

Then, length = (x+5)m

Area of a rectangle = Length x Breadth

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25 or x = -30

Hence, breadth x = 25m

=> Length = x + 5 = 25 + 5 = 30m.

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Q:

The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?

A) 20 m	B) 30 m
C) 40 m	D) 50 m

Answer & Explanation Answer: A) 20 m

Explanation:

Let breadth=x meters. Then, Length = $\frac{115 x}{100}$ meters

Given that, $x \times \frac{115 x}{100} = 460$

=> x = 20

Breadth = 20

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