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Q:

What is dual-mode operation?

Answer

In order to protect the operating systems and the system programs from the malfunctioning programs the two mode operations were evolved


System mode


User mode

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Q:

A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A) 551/15134 B) 1/2
C) 552/15379 D) 1/9
 
Answer & Explanation Answer: A) 551/15134

Explanation:

Total number of elementary events = 50C5
Given,third ticket =30

 

 

 

=> first and second should come from tickets numbered 1 to 29 = 29C2 ways and remaining two in 20C2 ways.

 

 

 

Therfore,favourable number of events = 29C2*20C2

 

 

 

Hence,required probability = 29C2*20C2/50C5 =551 / 15134

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Filed Under: Probability

Q:

Find the area of a square, one of whose diagonals is 3.8 m long.

A) 4.22 sq.m B) 5.22 sq.m
C) 6.22 sq.m D) 7.22 sq.m
 
Answer & Explanation Answer: D) 7.22 sq.m

Explanation:

Area of the square = 12×diagonal2=  1/2 * 3.8 * 3.8 = 7.22 sq.m

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What are the different job scheduling in operating systems?

Answer

Scheduling is the activity of the deciding when process will receive the resources they request.


FCS ---> FCSFS stands for First Come First Served. In FCFS the job that has been waiting the longest is served next.


Round Robin Scheduling--->Round Robin scheduling is a scheduling method where each process gets a small quantity of time to run and then it is preempted and the next process gets to run. This is called time-sharing and gives the effect of all the processes running at the same time


Shortest Job First ---> The Shortest job First scheduling algorithm is a nonpreemptive scheduling algorithm that chooses the job that will execute the shortest amount of time.


Priority Scheduling--->Priority scheduling is a scheduling method where at all times the highest priority process is assigned the resource.

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Q:

Find the probability of selecting 2 woman when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.

A) 1/5 B) 1/7
C) 1/6 D) 1/9
 
Answer & Explanation Answer: C) 1/6

Explanation:

Out of 9 persons,4 can be choosen in 9C4 ways =126.

 

Favourable events for given condition = 2C2*7C2= 21.

 

So,required probability = 21/126 =1/6.

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Filed Under: Probability

Q:

A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?

A) 13/42 B) 17/42
C) 5/42 D) 3/14
 
Answer & Explanation Answer: B) 17/42

Explanation:

3 letters can be choosen out of 9 letters in 9C3 ways.

 

More than one vowels ( 2 vowels + 1 consonant  or  3 vowels ) can be choosen in (4C2*5C1)+4C3 ways

 

Hence,required probability = 4C2*5C1+4C39C3 = 17/42

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Filed Under: Probability

Q:

Find the probability of selecting exactly 2 children when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.

A) 9/29 B) 10/21
C) 12/21 D) 14/19
 
Answer & Explanation Answer: B) 10/21

Explanation:

4 persons can be selected from 9 in 9C4 ways =126

 

Fvaourable events =4C2*5C2 =60

 

So,required probability = 60/126 = 10/21

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Filed Under: Probability

Q:

What are operating system services?

Answer



  • Program execution

  • I/O operations

  • File system manipulation

  • Communication

  • Error detection

  • Resource allocation

  • Accounting

  • Protection


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