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Q:

The 'M' Cooperative housing society has put up a notice at its gate that sales persons are not allowed inside the society

Assumptions:

1. All the sales persons stay away from 'M' Cooperation society

2. The security guard posted at the gate may be able to stop the sales persons entering the society

A) Only 1 is true	B) Only 2 is true
C) Either 1 or 2 is true	D) Both 1 and 2 follow

Answer & Explanation Answer: D) Both 1 and 2 follow

Explanation:

Since both the assumptions follow from the given statement,So both 1 and 2 are implicit

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Filed Under: Statement and Assumptions
Exam Prep: GRE

Q:

The diagonals of two squares are in the ratio of 2:5. Find the ratio of their areas.

A) 2:25	B) 3:25
C) 4:25	D) 6:25

Answer & Explanation Answer: C) 4:25

Explanation:

let the diagonals of the squares be 2x and 5x respectively

ratio of their areas = $\frac{1}{2} * {(2 x)}^{2} : \frac{1}{2} * {(5 x)}^{2}$ = 4:25

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.

A) 136	B) 146
C) 166	D) 176

Answer & Explanation Answer: D) 176

Explanation:

area of the room = 544 x 374 sq.cm

size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm

area of 1 tile = 34x34 sq cm

no. of tiles required = (544 x 374) / (34 x 34) = 176

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

A) 12	B) 24
C) 36	D) 48

Answer & Explanation Answer: B) 24

Explanation:

side of first square = 40/4 =10cm

side of second square = 32/4 = 8cm

area of third squre = 10² - 8² = 36 sq cm

side of third square = $\sqrt{36}$ = 6 cm

required perimeter = 6*4 = 24cm

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A rectangular grassy plot 110m by 65cm has a gravel path .5cm wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq.mt

A) 680rs	B) 480rs
C) 340rs	D) 320rs

Answer & Explanation Answer: A) 680rs

Explanation:

area of theplot = 110 * 65 = 7150 sq.m
area of the plot excluding the path = (110-5)* (65-5) = 6300 sq.m
area of the path = 7150 - 6300 =850 sq.m
cost of gravelling the path = 850 x (80/100) = 680 Rs

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110	B) 120
C) 130	D) 140

Answer & Explanation Answer: B) 120

Explanation:

let length = x and breadth = y then

2(x+y) = 46 => x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

=> x²+y²+2xy= 529

=> 289+ 2xy = 529

=> xy = 120

area = xy = 120 sq.cm

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.

A) 5	B) 4
C) 3	D) 2

Answer & Explanation Answer: B) 4

Explanation:

let the inner and outer radii be r and R meters
then, $2 πr$ = 352/7

=> r = (352/7) * (7/22) * (1/2) = 8m
$2 πR$ = 528/7

=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If the radius of a circle is decreased by 50% , find the percentage decrease in its area.

A) 75%	B) 65%
C) 35%	D) 25%

Answer & Explanation Answer: A) 75%

Explanation:

let original radius = r and new radius = (50/100) r = r/2

original area = ${πr}^{2}$ and new area = $π {(r / 2)}^{2}$

decrease in area = $3 {πr}^{2} / 4$ * $\frac{1}{{πr}^{2}}$ *100 = 75%

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

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