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Q:

What is the number of rectangles in the following figure?

A) 6 B) 7
C) 9 D) 11
 
Answer & Explanation Answer: C) 9

Explanation:

The simplest rectangles are AEHG, EFJH, FBKJ, JKCL and GILD i.e 5 in number.

The rectangles composed of two components each are AFJG and FBCL i.e 2 in number

Only one rectangle namely AFLD is composed of three components and only one rectangle namely ABCD is composed of five components.

Thus, there are 5 + 2 + 1 + 1 = 9 rectangles in the given figure.

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Filed Under: Analytical Reasoning

Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years . Then B's age 10 years ago be 2x years





 Total of their present ages = x + 10 + 2x + 10


= 3x+20


= 3 * 5 + 20 = 35 years


 

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Subject: Problems on Ages

Q:

The ratio of the father's age to the son's age is 3 : 1. The product of their ages is 147. The ratio of their ages after 5 years will be?

Answer

Let father's age be 3x and son's age be x years




Father's age after 5 years = 3x + 5 = 26 years


Son's age after 5 years = x + 5 = 12 years


 Ratio of father's and son's ages = 26 : 12 = 13 : 6


 

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Subject: Problems on Ages

Q:

The average age of a couple was 26 years at the time of marriage. After 11 years of marriage, the average age of the family with 3 children become 19 years. The average age of the children is

Answer

The average age of a couple = 26 years.


Total age of couples = 26 x 2 = 52 years


 Total age of couple after 11 years = (52 + 2 * 11 ) = 74 years


Suppose average age of 3 children after 11 years is 3x years.



The average age of children is 7 years.

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Subject: Problems on Ages

Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new student is?

Answer

Total age of 10 students = 150 years


Total age of 15 students = 240 years


Total age of 5 new students = 240 - 150 = 90 years


 Average age of 5 new students = 90/5 = 18 years.

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Subject: Problems on Ages

Q:

8 years ago Ramana's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter. Find the present age of Ramana?

Answer

Let Ramana's age 8 years ago be x years and mother's age 8 years ago be 5x


2(x + 16) = 5x + 16


2x + 32 = 5x + 16


3x = 16 


  years


Hence, Present age of Ramana =  years

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Subject: Problems on Ages

Q:

A man said to his son, "I was two-thirds of your present age when you were born". IIf the present age of the man is 48 years, find the present age of the son.

Answer

Let the Present age of the son be P, which means he was born P years ago.At the time the son was born, the age of the man was : (48 - P). So, according to the statement made by the man, his age when the son was born should be equal to 2/3 of P.


Therefore, 


Solving, we get P = 28.8 years; which is the present age of the son.

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Subject: Problems on Ages

Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

Answer

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.


So, 5 years ago, as the ratio of their ages was 5 : 7, we can write  (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

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Subject: Problems on Ages