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Q:

What is the importance of having an emulator within the Android environment?

Answer

The emulator lets developers “play” around an interface that acts as if it were an actual mobile device. They can write and test codes, and even debug. Emulators are a safe place for testing codes especially if it is in the early design phase.

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Subject: Application Development

Q:

From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

A) 75 litres	B) 100 litres
C) 150 litres	D) 120 litres

Answer & Explanation Answer: D) 120 litres

Explanation:

$\frac{w i n e (l e f t)}{w i n e (a d d e d)} = \frac{343}{169}$

It means $\frac{w i n e (l e f t)}{w i n e (i n i t i a l a m o u n t)} = \frac{343}{512}$ (since 343 + 169 = 512)

Thus, $343 x = 512 x {(1 - \frac{15}{k})}^{3}$

$\frac{343}{512} = {(\frac{7}{8})}^{3} = {(1 - \frac{15}{k})}^{3}$

$(1 - \frac{15}{k}) = \frac{7}{8} = (1 - \frac{1}{8})$

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg	B) 1 kg
C) 1.5 kg	D) None of these

Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was k, then

$512 = k {(1 - \frac{1}{5})}^{4} o r 512 = k {(\frac{4}{5})}^{4}$

=> $k = \frac{512 \times 625}{256}$

=> k = 1250

Hence initially the honey in the jar = 1.25 kg

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Filed Under: Alligation or Mixture
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is

A) 81.92L	B) 96L
C) 118.08L	D) None of these

Answer & Explanation Answer: C) 118.08L

Explanation:

The amount of petrol left after 4 operations

= $200 \times {(1 - \frac{40}{200})}^{4}$

= $200 \times {(\frac{4}{5})}^{4}$

= $200 \times (\frac{256}{625})$

= 81.92 litres

Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

Can I call an XLM macro from within Excel VB?

Answer

With the help of Excel App instance. we can execute a Macro in VB code.

EXcelAppInstance.Application.Run("MacroName")

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Subject: Microsoft Interview

Q:

How do you check the syntax of a JCL without running it?

Answer

TYPERUN=SCAN on the JOB card or use JSCAN.

TYPERUN=HOLD on the job card.

it is used for syntatical checks and direct job to spool and hold it.

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Subject: Mainframe Interview

Q:

How do you fix the problem associated with VSAM out of space condition?

Answer

Define new VSAM dataset allocated with more space.

Use IDCAMS to REPRO the old VSAM file to new VSAM dataset.

Use IDCAMS to ALTER / RENAME the old VSAM dataset to DELETE the old VSAM datset.

Use IDCAMS to ALTER / RENAME the new VSAM dataset to the name of the original VSAM dataset.

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Subject: Mainframe Interview

Q:

How does IDMS communicate with CICS?

Answer

They communicate via service MVS request calls.

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Subject: Mainframe Interview

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