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Q:

If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

A) 10 B) 11
C) 12 D) 13
 
Answer & Explanation Answer: D) 13

Explanation:

Area = 12*diagonal1*12diagonal2 = 12*24*10 sq.cm  

 

12*daigonal1=12*24=12cm 

 

12*diagonal2=12*10=5cm 


side of a rhombus = (12)² + (5)² = 169      => AB = 13cm

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Q:

A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

A) 136 B) 236
C) 336 D) 436
 
Answer & Explanation Answer: C) 336

Explanation:

let ABCD be the given parallelogram 

area of parallelogram ABCD = 2 x (area of triangle ABC) 

now a = 30m, b = 14m and c = 40m

 s=1/2 x (30+14+40) = 42 

 

Area of triangle ABC = ss-as-bs-c  

 

= 4212282= 168sq m 

area of parallelogram ABCD = 2 x 168 = 336 sq m

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Q:

A special member function of a class, which is invoked automatically whenever an object goes out of the scope is called

A) Constructor B) Destructor
C) Friend function D) None of the above
 
Answer & Explanation Answer: B) Destructor

Explanation:

Destructor is a special member function of a class, which is invoked automatically whenever an object goes out of the scope. It has the same name as its class with a tilde character prefixed.

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Q:

An equilateral triangle is described on the diagonal of a square. What is the ratio of the area of the triangle to that of the square?

A) 1:2 B) 1:3
C) 2:3 D) 3^(1/2) :2
 
Answer & Explanation Answer: D) 3^(1/2) :2

Explanation:

area of a square = a² sq cm

 

length of the diagonal = 2a cm

 

area of equilateral triangle with side  2a= 34*2a2
required ratio = 34*2a2:a2=3:2

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Q:

The diagonals of two squares are in the ratio of 2:5. Find the ratio of their areas.

A) 2:25 B) 3:25
C) 4:25 D) 6:25
 
Answer & Explanation Answer: C) 4:25

Explanation:

let the diagonals of the squares be 2x and 5x respectively

 

 

 

ratio of their areas = 12*2x2 :12*5x2 = 4:25

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Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110 B) 120
C) 130 D) 140
 
Answer & Explanation Answer: B) 120

Explanation:

let length = x and breadth = y then  

2(x+y) = 46         =>   x+y = 23  

x²+y² = 17² = 289  

now (x+y)² = 23² 

=> x²+y²+2xy= 529 

=> 289+ 2xy = 529

=> xy = 120  

area = xy = 120 sq.cm

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Q:

A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?

A) 126 B) 120
C) 146 D) 156
 
Answer & Explanation Answer: A) 126

Explanation:

There are 8 students and the maximum capacity of the cars together is 9.


We may divide the 8 students as follows


Case I: 5 students in the first car and 3 in the second
Case II: 4 students in the first car and 4 in the second


Hence, in Case I: 8 students are divided into groups of 5 and 3 in8C3 ways.


Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4ways.


Therefore, the total number of ways in which 8 students can travel is:
8C3+8C4=56 + 70= 126

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Q:

One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?

A) 110 B) 120
C) 130 D) 140
 
Answer & Explanation Answer: B) 120

Explanation:

Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8 =120 sq. m

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