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Q:

Seats for Mathematics, Physics and Biology in a school are in the ratio 5:7:8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ?

A) 1:2:3 B) 2:3:4
C) 3:4:5 D) 4:5:6
 
Answer & Explanation Answer: B) 2:3:4

Explanation:

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
⇒ [(140/100) × 5x],[(150/100) × 7x] and [(175/100) × 8x]
⇒ 7x, 21x/2 and 14x.

⇒ The required ratio =7x : 21x/2 : 14x
⇒ 14x : 21x : 28x
⇒ 2 : 3 : 4

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Filed Under: Ratios and Proportions

Q:

A sum of Rs.312 was divided among 100 boys and girls in such a way that the boy gets Rs.3.60 and each girl Rs. 2.40 the number of girls is

A) 35 B) 40
C) 45 D) 50
 
Answer & Explanation Answer: B) 40

Explanation:

Step (i): Let x be the number of boys and y be the number of girls.
Given total number of boys and girls = 100
x+y=100 -------------- (i)

Step (ii): A boy gets Rs. 3.60 and a girl gets Rs. 2.40
The amount given to 100 boys and girls = Rs. 312
3.60x + 2.40y = 312 -------------- (ii)

Step (iii):
Solving (i) and (ii)
3.60x + 3.60y = 360 --------- Multiply (i) by 3.60
3.60x + 2.40y = 312 --------- (ii)
1.20y = 48
y = 48 / 1.20
= 40

 Number of girls = 40

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Filed Under: Ratios and Proportions

Q:

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

A) 2:5 B) 3:5
C) 4:5 D) 5:4
 
Answer & Explanation Answer: C) 4:5

Explanation:

Let the third number be x.

Then, first number = 120% of x =120x/100 = 6x/5  


Second number =150% of x = 150x/100 = 3x/2

Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5

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Filed Under: Ratios and Proportions

Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. EJO, TYD, INS, XCH ?

A) NRW B) NSX
C) MRW D) MSX
 
Answer & Explanation Answer: C) MRW

Explanation:

There is a gap of four letters between the first and second, the second and third letters.
There is a gap of four letters between the last letter and the first letter of the next term.

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Filed Under: Number Series

Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. BMO, EOQ, HQS, ?

A) KSU B) SOV
C) SOW D) LMN
 
Answer & Explanation Answer: A) KSU

Explanation:

The first letter moves 3 steps forward. The second and third letters move 2 steps forward.

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Filed Under: Number Series

Q:

A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.

A) 10 B) 12
C) 15 D) 18
 
Answer & Explanation Answer: A) 10

Explanation:

Let the quantity of alcohol and water be 4x litres and 3x litres respectively

 

4x/(3x+5) = 4/5 

 

20x = 4(3x+5)

 

8x = 20

 

x = 2.5

 

Quantity of alcohol = (4 x 2.5) litres = 10 litres.

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Filed Under: Ratios and Proportions

Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?).Choose the missing terms out of the given alternatives. 2Z5, 7Y7, 14X9, 23W11, 34V13, ?

A) 47U15 B) 47V14
C) 45U15 D) 27U24
 
Answer & Explanation Answer: A) 47U15

Explanation:

The first numbers increase by 5, 7, 9, 11....
The letters move one step backward.
The last numbers are consecutive odd numbers.

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Filed Under: Number Series

Q:

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.

A) 360, 160, 200 B) 160, 360, 200
C) 200, 360,160 D) 200,160,300
 
Answer & Explanation Answer: C) 200, 360,160

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

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Filed Under: Ratios and Proportions