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Q:

The mean temperature of Monday to Wednesday was 37C and of Tuesday to Thursday was 34C . If the temperature on Thursday was (4/5) th that of Monday, the temperature on Thursday was?

Answer

$\inline \fn_jvn M+T+W =(37\times 3)^{0}=111^{0}C$ -----------(1)

$\inline \fn_jvn T+W+Th=(34\times 3)^{0}=102^{0}C$

$\inline \fn_jvn \Rightarrow T+W+\frac{4}{5}M = 102^{0}C$ --------------(2)

(1) - (2) gives

$\inline \fn_jvn \frac{1}{5}$ th of temperature on Monday = $111^{0}-102^{0}=9^{0}C$

$\inline \fn_jvn \Rightarrow$ Temperature on Monday = $\inline \fn_jvn 45^{0}C$

$\inline \fn_jvn \therefore$ Temperature on Thursday = $\inline \fn_jvn \frac{4}{5}\times 45^{0}=36^{0}$

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Subject: Average

Q:

A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?

Answer

Let the average after 7th inning = x

Then average after 16th inning = x - 3

16(x-3)+87 = 17x

x = 87 - 48 = 39

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Subject: Average Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

The average of 9 results is 50. The average of first four results is 52 and average of last four results is 49 . what is the fifth result?

Answer

Total of results = 50 x 9 = 450

Total of first four results = 52 x 4 = 208

Total of Last four results = 49 x 4 = 196

Hence the fifth result = 450 - (208 + 196) = 46

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Subject: Average

Q:

A man covers a journey from Meerut to Delhi by a car at an average speed of 40 km/hr. He returns back by scooter with an average speed 24 km/hr. Find his average speed during the whole journey?

Answer

Average speed = $\frac{2xy}{x+y}$ km/hr

= $\frac{2\times 40\times 24}{40+24}=30$ km/hr

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Subject: Average

Q:

What smallest number of 6 digit is divisible by 111?

Answer

Smallest number of 6 digits is 100000

on dividing 100000 by 111 we get 100 as remainder

$\inline \fn_jvn \therefore$ Number to be added = (111 -100) = 11

$\inline \fn_jvn \therefore$ Required Number = 100011

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Subject: Numbers

Q:

The value of

$\left [ \frac{2^{n}+2^{n-1}}{2^{n+1}-2^{n}} \right ]$ is:

Answer

$\frac{2^{n} + \frac{2^{n}}{2}}{2 x 2^{n} - 2^{n}} = \frac{2^{n} (1 + \frac{1}{2})}{2^{n} (2 - 1)} = \frac{3}{2}$

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Subject: Numbers Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

Q:

The difference of two numbers is 11 and (1/5)th of their sum is 9. The numbers are

Answer

Let the numbers be x and (x-11)

$\frac{1}{5}\times (x+x-11)=9$

$\inline \fn_jvn \Rightarrow$ x = 28

$\inline \fn_jvn \therefore$ Another Number is (28 - 11) = 17

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Subject: Numbers

Q:

A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?

Answer

Number = ( 779 x a) + 47, where "a" is the quotient

= (19 x 41 x a) + (19 x 2) + 9

= 19 x (41a + 2) + 9

= 19 x (New quotient) + 9

$\inline \fn_jvn \therefore$ Required remainder = 9

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Subject: Numbers

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