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Q:

In the following question a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. ab __ d __ aaba __ na _ badna _ b

A) andaa B) babda
C) dbanb D) badna
 
Answer & Explanation Answer: A) andaa

Explanation:

The series is abadna/abadna/abadna/ab.
The pattern 'abadna' is repeated

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Filed Under: Number Series

Q:

In each of the following questions a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. _ op _ mo _ n _ _ pnmop _

A) mnpmon B) mpnmop
C) mnompn D) mnomon
 
Answer & Explanation Answer: A) mnpmon

Explanation:

The pattern 'mopn' is repeated.

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Q:

A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train  pass the jogger ?

A) 48 sec B) 36 sec
C) 18 sec D) 72 sec
 
Answer & Explanation Answer: B) 36 sec

Explanation:

Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr =(36*5/18) m/sec  = 10 m/sec

Distance to be covered =(240 + 120)m = 360 m

 Time taken = 360/10 sec = 36 sec

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Filed Under: Problems on Trains

Q:

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

A) 500 B) 400
C) 360 D) 480
 
Answer & Explanation Answer: B) 400

Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18)  m/s = 25 m/s 


Time = 12 s

Distance/time = speed 

=>3x/12 = 25 (25*12)/3 

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y     [where y is the length of the platform] 

x =100m => 200+y = 45* 40/3
y = 400m

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Filed Under: Problems on Trains

Q:

In the following question a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. ba_ba_bac_acb_cbac

A) bbca B) ccba
C) cbac D) aacb
 
Answer & Explanation Answer: B) ccba

Explanation:

The series is bac/bac/bac/bac/bac/bac.
The pattern bac is repeated.

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Filed Under: Number Series

Q:

Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?

A) 10.30 B) 10
C) 8.45 D) 9.30
 
Answer & Explanation Answer: B) 10

Explanation:

Assume both trains meet after x hours after 7 am

Distance covered by train starting from P in x hours = 20x km

Distance covered by train starting from Q in (x-1) hours = 25(x-1)

Total distance = 110

=> 20x + 25(x-1) = 110

=> 45x = 135

=> x= 3

Means, they meet after 3 hours after 7 am, ie, they meet at 10 am

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Filed Under: Problems on Trains

Q:

In the following question, various terms of an alphabet series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. BAZ, DCY, FEX, ?

A) FXW B) FEY
C) HGW D) EFX
 
Answer & Explanation Answer: C) HGW

Explanation:

The first letter moves two steps forward.
The second letter moves 2 steps forward.
The third letter moves one step backward.

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Filed Under: Number Series

Q:

A train of length 110 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A) 10 B) 8
C) 6 D) 4
 
Answer & Explanation Answer: C) 6

Explanation:

Distance = 110 m

Relative speed = 60 + 6 = 66 kmph (Since both the train and the man are in moving in opposite direction)

= (66*5/18)  m/sec = 55/3  m/sec

Time taken to pass the man = (100*3/55) = 6 s

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Filed Under: Problems on Trains