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Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?

Answer

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

$\inline \therefore$ Average age of 5 new students = $\frac{90}{5}$ = 18 years

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Subject: Problems on Ages

Q:

The Average age of 12 men is decreased by one year when two of them having ages 28 years and 32 years are replaced by two women of same age . The age of a women is?

Answer

Suppose age of each women be W and average age of 12 men be x

$\therefore \frac{12x-28-32+2W}{12}=x-1$

$\therefore W=24$

Hence , each woman's age = 24 years

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Subject: Problems on Ages

Q:

8 years ago Rama's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter . Find the present age of Rama?

Answer

Let Rama's age 8 years ago be x years and mother's age 8 years ago be 5x

$\Rightarrow 2(x+16)= 5x+16$

$2x+32=5x+16$

$3x=16$

$x=\frac{16}{3}$ years

Hence, present age of Rama = $x+8=\frac{16}{3}+8=\frac{40}{3}=13\frac{1}{3}$ years

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Subject: Problems on Ages

Q:

The average of ages of threee persons is 60 years . Those ages are in the proportion of 1:2:3. what is the age of the youngest one among them?

Answer

Suppose the ages of three persons are x, 2x, 3x years respectively

$\Rightarrow \frac{x+2x+3x}{3}=60$

$\Rightarrow 6x=180$

$\Rightarrow x=30$

Hence, age of youngest person = x = 30 years.

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Subject: Problems on Ages

Q:

The Age of Ashok , Deepak and Ramu are in the proportion of 3:5:6. If the difference between the ages of Deepak and Ramu is 5 years . what is Ashok's age in years?

Answer

Suppose the ages of Ashok, Deepak and Ramu are 3x, 5x and 6x years respectively.

$6x-5x=5\: \: \Rightarrow x=5$

Hence , Ashok's age = $3x$ = $3\times 5$ = 15 years

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Subject: Problems on Ages

Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years

Then B's age 10 years ago be 2x yeats

$\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}$

$\inline \Rightarrow 4(x+10)=3(2x+10)$

$\inline \Rightarrow x=5$

$\inline \therefore$ Total of their present ages = $x+10+2x+10$

= $3x+20$

= 35 years

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Subject: Problems on Ages

Q:

One year ago the ratio between Mohan and Ashok's age was 4:3 after one yerar the rato of their ages will be 5:4 . what is the sunm of their present ages in years.

Answer

Let their ages one year ago be 4x and 3x years

$\Rightarrow \frac{4x+2}{3x+2}=\frac{5}{4}\Rightarrow 4(4x+2)=5(3x+2)$

$\Rightarrow x=2$

$\therefore$ Sum of their present ages =(4x +1+3x+1) = 16 years.

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Subject: Problems on Ages

Q:

July 14 is celebrated every year as a national holiday in France. On this day in 1789,

A) The member of the third estate declared themselves the National Assembly	B) Workers, peasants and other non propertied classes were given political rights
C) Napoleon become the Emperor	D) The fall of Bastille took place

Answer & Explanation Answer: D) The fall of Bastille took place

Explanation:

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Filed Under: World History

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