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Q:

How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?

A) 36 Kg	B) 42 Kg
C) 54 Kg	D) 63 Kg

Answer & Explanation Answer: D) 63 Kg

Explanation:

By the rule of alligation:

C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind

Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.

Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.

Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.

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Filed Under: Alligation or Mixture

Q:

8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16 : 65. How much wine the cask hold originally?

A) 18 litres	B) 24 litres
C) 32 litres	D) 42 litres

Answer & Explanation Answer: B) 24 litres

Explanation:

Let the quantity of the wine in the cask originally be x litres

Then, quantity of wine left in cask after 4 operations = $[x {(1 - \frac{8}{x})}^{4}]$ litres

$∴ [\frac{x {(1 - \frac{8}{x})}^{4}}{x}] = \frac{16}{81}$

$\Rightarrow {[1 - \frac{8}{x}]}^{4} = {(\frac{2}{3})}^{4}$

$\Rightarrow x = 24$

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Filed Under: Alligation or Mixture

Q:

The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs.20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is

A) Rs. 19.50	B) Rs. 19
C) Rs. 18	D) Rs. 18.50

Answer & Explanation Answer: C) Rs. 18

Explanation:

Let the price of the mixed variety be Rs. x per kg. By the rule of alligation, we have :

Cost of 1 kg of type 1 rice Cost of 1 kg of type 2 rice

$∴$ (20-x)/(x-15) = 2/3

$\Rightarrow$ 60 - 3x = 2x - 30

$\Rightarrow$ x = 18.

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Filed Under: Alligation or Mixture

Q:

A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

A) 10	B) 20
C) 21	D) 25

Answer & Explanation Answer: C) 21

Explanation:

Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively

Quantity of A in mixture left = $(7 x - \frac{7}{12} \times 9) = (7 x - \frac{21}{4})$ litres.

Quantity of B in mixture left = $(5 x - \frac{5}{12} \times 9) = (5 x - \frac{15}{4})$ litres.

$\frac{(7 x - \frac{21}{4})}{(5 x - \frac{15}{4}) + 9} = \frac{7}{9}$

$\Rightarrow \frac{28 x - 21}{20 x + 21} = \frac{7}{9}$

$\Rightarrow x = 3$

So, the can contained 21 litres of A.

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Filed Under: Alligation or Mixture

Q:

The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is

A) 15 cm	B) 25 cm
C) 35 cm	D) 42 cm

Answer & Explanation Answer: C) 35 cm

Explanation:

Required Length = H.C.F of 700 cm, 385 cm and 1295 c

= 35 cm.

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Filed Under: HCF and LCM

Q:

An observer 1.6 m tall is $20 \sqrt{3}$ away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of the tower is:

A) 21.6 m	B) 23.2 m
C) 24.72 m	D) None of these

Answer & Explanation Answer: A) 21.6 m

Explanation:

Draw BE // CD

Then, CE = AB = 1.6 m,

BE = AC =

$\frac{D E}{\tan 30} = > D E = \tan 30 x 20 \sqrt{3} = > D E = \frac{1}{\sqrt{3}} x 20 \sqrt{3} = 20$

Therefore, CD = CE + DE = (1.6 + 20) m = 21.6 m.

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Filed Under: Height and Distance
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Q:

Which is the highest waterfall in the world ?

Answer

Angel, Venezuela

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Subject: Longest, Shortest, Deepest

Q:

Which is Largest library in the world ?

Answer

United State Library of Congress, Washington D.C.

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Subject: Longest, Shortest, Deepest

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