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Q:

A semicircular shaped window has diameter of 63cm. Its perimeter equals

A) 162 B) 132
C) 142 D) 172
 
Answer & Explanation Answer: A) 162

Explanation:

perimeter of window = πr+2r 

= [(22/7) x (63/2) + 63] = 99+63 = 162 cm

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Filed Under: Area
Exam Prep: Bank Exams
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Q:

If the area of a square with side a s equal to the area of a triangle with base a, then the altitude of the triangle is

A) a B) 2a
C) 5a D) 3a
 
Answer & Explanation Answer: B) 2a

Explanation:

Area of a square with side a = a² sq unts

Area of a triangle with base a = (1/2) * a * h sq.unts

a² =1/2 *a *h

=> h = 2a

altitude of the triangle is 2a

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Q:

The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

A) 12 B) 24
C) 36 D) 48
 
Answer & Explanation Answer: B) 24

Explanation:

side of first square = 40/4 =10cm

 

side of second square = 32/4 = 8cm

 

area of third squre = 10² - 8² = 36 sq cm

 

side of third square = 36 = 6 cm

 


required perimeter = 6*4 = 24cm

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Q:

The charge on positron is equal to the charge on

A) proton B) electron
C) alpha- particle D) neutron
 
Answer & Explanation Answer: A) proton

Explanation:
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Filed Under: Chemistry

Q:

Other things being equal, would an investor prefer an interest rate of 10.5% compounded monthly or 11% compounded annually for a two-year investment?

A) 1232 B) 1243
C) 1254 D) 1262
 
Answer & Explanation Answer: A) 1232

Explanation:

i=j/m

 

FV=  PV(1+  i)^n 

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Filed Under: Compound Interest
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Q:

Divide Rs. 1301 between A and B, so that the amount of A after 7 years is equal to the amount of B after 9 years, the interest being compounded at 4% per annum.

A) Rs.625 B) Rs.626
C) Rs.286 D) Rs.627
 
Answer & Explanation Answer: A) Rs.625

Explanation:

Let the two parts be Rs. x and Rs. (1301 - x).

 x1+41007=1301-x1+41009

 x1301-x=1+41002=2625*2526

 

=> 625x=676(1301-x) 

1301x=676 x 1301x=676.
So,the parts are rs.676 and rs.(1301-676)i.e rs.676 and rs.625

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Filed Under: Compound Interest
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Q:

A rectangular block 6 cm by 12 cm by 15 cm is cut up into an exact number of equal cubes. Find the least possible number of cubes.

A) 30 B) 40
C) 10 D) 20
 
Answer & Explanation Answer: B) 40

Explanation:

Volume of the block = (6 x 12 x 15) cu.cm = 1080 cu.cm 

Side of the largest cube = H.C.F. of 6 cm, 12 cm, 15 cm 

                                   = 3 cm.

 

Volume of this cube  = (3 x 3 x 3) cu.cm = 27 cu.cm 

Number of cubes =108027 = 40.

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Q:

One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.

A) 1/3 B) 1/2
C) 1/4 D) 1/6
 
Answer & Explanation Answer: B) 1/2

Explanation:

Total number of elementary events = 52

 

There are 26 red cards,out of which one red card can be drawn in 26C1 ways =26.

 

So,required probability = 26/52 = 1/2

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Filed Under: Probability