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Q:

The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ?

A) 87	B) 81
C) 83	D) 85

Answer & Explanation Answer: A) 87

Explanation:

Cp1 = p2 - p1 ,
Cp2 = p3 - p2
..
..
..
Cp23 = p24 - p23
Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)
All terms get cancelled, except p1 = 2 and p24 = 89
So Sum = -p1 + p24
Sum of series = -2 + 89 = 87

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Filed Under: Problems on Numbers
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Q:

What should come in place of the question mark(?) in the following questions ?

$3 \frac{1}{6} + 4 \frac{1}{2} - 2 \frac{2}{3} - 1 \frac{11}{12} = ?$

A) 1 7/12	B) 1 5/12
C) 3 7/12	D) 3 1/12

Answer & Explanation Answer: D) 3 1/12

Explanation:

? = (3 + 4 - 2 - 1) + ( 1/6 + 1/2 - 2/3 - 11/12)

= 4 + [(2+6-8-11)/12]

= 4 - (11/12 )= 31/12.

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Filed Under: Mathematical Operations
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Q:

Correct the underlined words in the following sentence if necessary from the options below ?

Your admission into this university will be dependent on the marks you score in the entrance examination.

A) is depending	B) will depend
C) depending	D) depends

Answer & Explanation Answer: B) will depend

Explanation:

It is a future condition and hence 'will depend' is more appropriate.

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Filed Under: Alphabet Test

Q:

What will come in place of the question mark (?) in the following questions ?

22% of ? + 166.64 = 340

A) 788	B) 786
C) 784	D) 792

Answer & Explanation Answer: A) 788

Explanation:

(kx22)/100 = 340 - 166.64 = 173.36
k = (173.36 x 100)/22
k = 788

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Filed Under: Numbers
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Q:

Correct underlined words if necessary in the following sentence ?

Have you been more careful, the accident could have been averted.

A) Have you been	B) If you have been
C) Had you been	D) If you could have been

Answer & Explanation Answer: C) Had you been

Explanation:

As the sentence talks about the past it is apt to say. 'Had you been more careful ...'.

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Filed Under: Alphabet Test
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Q:

If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ?

A) Rs. 1033.33	B) Rs. 1024
C) Rs. 1148.14	D) Rs. 1245.32

Answer & Explanation Answer: A) Rs. 1033.33

Explanation:

Let
P's capital = p,
Q's capital = q and
R's capital = r.
Then

6p = 8q = 12r
=> 3p = 4q = 6r
=>q = 3p/4
r = 3p/6 = p/2
P : Q : R = p : 3p/4 : p/2
= 4 : 3 : 2
R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.

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Filed Under: Partnership
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Q:

If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ?

A) 3	B) 2
C) 1	D) 0

Answer & Explanation Answer: D) 0

Explanation:

Let assume the value of a,b &c that will satisfy the equation.
so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1
here all three cases satisfy the equation
assume any one a=1,b=1,c= -1

Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0

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Filed Under: Numbers
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Q:

Find the remainder when $6^{29}$ is divided by 5 ?

A) 0	B) 1
C) 3	D) 5

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