Sir Sandford Fleming, (January 7, 1827 – July 22, 1915) was a Scottish Canadian engineer and inventor. Born and raised in Scotland, he emigrated to colonial Canada at the age of 18. He proposed worldwide standard time zones, designed Canada's first postage stamp.

Carefully obsrving the given arrangement, we find the following pattern:
We observe that,first all the words with the highest number of letters are arranged in the alphabetical order, followed by the words with the second highest number of letters and so on.However, the position of only one word is altered at each step.
Input: more fight cats cough sough acts idea
Step1: cough more fight cats sough acts idea
Step2: cough fight more cats sough acts idea
Step3: cough fight sough more cats acts idea
Step4: cough fight sough acts more cats idea
Step5: cough fight sough acts cats more idea
Step6: cough fight sough acts cats idea more

Hence, the answer is A

Carefully obsrving the given arrangement, we find the following pattern:
We observe that the given numbers are arranged in descending order (from left to right), altering the position of only one number in each step, followed by the other numbers as it is. The process continues till the whole set of numbers is arranged in the descending order.

Step1: 28 16 09 24 15 04
Step2: 28 24 16 09 15 04
Step3: 28 24 16 15 09 04

Hence, the answer is B

Obsrving the given arrangement, we find the following pattern:
If we arrange the words in the given input in the alphabetical order and then label them as 1,2,3,4,5,6, then the last step contains the words in the order 6,1,5,2,4,3. However, the position of only one word is alteredat each step.
Input:car on star quick demand fat
Step1: star car on quick demand fat
Step2: star car quick on demand fat
Step3: star car quick demand on fat

Hence, the answer is C

Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5.

So, there is one way of doing it.

Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

Required number of numbers = (1 x 5 x 4) = 20.

Total number of flowers = (8+7+6) = 21.

Let E = event that the flower drawn is neither red nor green. 

= event taht the flower drawn is blue. 

--> n(E)= 7 

--> P(E)=  721=13 

Let S be the sample space. Then,
n(s) = number of ways of drawing 4 pearls out of 14

= C414 ways = 14×13×12×114×3×2×1= 1001

Let E be the event of drawing 4 pearls of the same colour.
Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5)

  ⇒C15+ C44+ C15 = 5+1+5 =11

 P(E) = n(E)n(S)=111001=191  

 Required probability = 1-191=9091

 Using pythagorus rule, 

 x2=122+52

 --> x = 13